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2. In a single-phase circuit VA = 11 + j16 V and Vg = 12 – j12 V with respect to a reference node 0. Calculate VAB. 3. What is the rms value of a square wave with an amplitude of 10 A and a frequency of 1 Hz? 4. A sinusoidal current wave has an rms value of 20 A. What is the average value of one- half cycle?

2. In a single-phase circuit VA = 11 + j16 V and Vg = 12 – j12 V with respect to a reference node 0. Calculate VAB. 3. What is the rms value of a square wave with an amplitude of 10 A and a frequency of 1 Hz? 4. A sinusoidal current wave has an rms value of 20 A. What is the average value of one- half cycle?

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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1. Wavelength is the distance traveled by an electronic wave during the time of one cycle. Given a wave having a frequency of 100 kHz, what is the waelength? 2. In a single-phase circuit VA = 11+ j16 V and VB = 12 -j12 V with respect to a reference node 0. Calculate VAB. 3. What is the rms value of a square wave with an amplitude of 10 A and a frequency of 1 Hz? 4. A sinusoidal current wave has an rms value of 20 A. What is the average value of one- half cycle? 5. Three alternating currents are given by i1 iz = 30 sin (wt + 90°); iz 141 sin(wt + 45°); = 20 sin (wt – 120°). Find the equation of the resultant current.
Transcribed Image Text:1. Wavelength is the distance traveled by an electronic wave during the time of one cycle. Given a wave having a frequency of 100 kHz, what is the waelength? 2. In a single-phase circuit VA = 11+ j16 V and VB = 12 -j12 V with respect to a reference node 0. Calculate VAB. 3. What is the rms value of a square wave with an amplitude of 10 A and a frequency of 1 Hz? 4. A sinusoidal current wave has an rms value of 20 A. What is the average value of one- half cycle? 5. Three alternating currents are given by i1 iz = 30 sin (wt + 90°); iz 141 sin(wt + 45°); = 20 sin (wt – 120°). Find the equation of the resultant current.
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