2. If you very close to the surface on a conductor it will look flat. Just as the Earth appears flat to us because we are on the surface. We want to find the electric field at E a point P just outside the conductor. Assume the conducting surface near P has a positive charge per area n. We draw a Gaussian cylinder of radius R and height 2h cutting through the surface. h h, a. What is the flux through the curved portion of the Gaussian surface? Write the answer in terms of the Conductor unknown electric field E, R and/or h. b. What is the flux through the bottom endcap? С. What is the flux through the top endcap?

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2. If you very close to the surface on a conductor it will
look flat. Just as the Earth appears flat to us because we
R
are on the surface. We want to find the electric field at
E
a point P just outside the conductor. Assume the
conducting surface near P has a positive charge per
h
area n. We draw a Gaussian cylinder of radius R and
height 2h cutting through the surface.
а.
What is the flux through the curved portion of the
Gaussian surface? Write the answer in terms of the
Conductor
unknown electric field E, R and/or h.
b. What is the flux through the bottom endcap?
С.
What is the flux through the top endcap?
d. Write the charge enclosed by the Gaussian surface in terms of 7, R and/or h?
е.
Use Gauss's law to find the electric field just outside the conductor.
Transcribed Image Text:2. If you very close to the surface on a conductor it will look flat. Just as the Earth appears flat to us because we R are on the surface. We want to find the electric field at E a point P just outside the conductor. Assume the conducting surface near P has a positive charge per h area n. We draw a Gaussian cylinder of radius R and height 2h cutting through the surface. а. What is the flux through the curved portion of the Gaussian surface? Write the answer in terms of the Conductor unknown electric field E, R and/or h. b. What is the flux through the bottom endcap? С. What is the flux through the top endcap? d. Write the charge enclosed by the Gaussian surface in terms of 7, R and/or h? е. Use Gauss's law to find the electric field just outside the conductor.
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