If ƒ (x, y) = log (x² + y²), then f +f, is equal to XX yy 1 (a) x² + y² (b) 0 2 1,² - x² (c) (d) (x² + y²)² x² - y² (x² + y²) ²
If ƒ (x, y) = log (x² + y²), then f +f, is equal to XX yy 1 (a) x² + y² (b) 0 2 1,² - x² (c) (d) (x² + y²)² x² - y² (x² + y²) ²
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 52RE
Related questions
Question
![2. Iff(x, y) = log (x² + y²), then fu + f is equal to
1
(a)
+ y²
(b) 0
2-²
2-x²
(d)
(x+y=²
(x2+y2²
(c)
x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F21bf5d34-e839-40ce-aba4-02405014421a%2F9897efb9-2491-4091-afcb-cb91e0e5cf6f%2Flh8i92v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Iff(x, y) = log (x² + y²), then fu + f is equal to
1
(a)
+ y²
(b) 0
2-²
2-x²
(d)
(x+y=²
(x2+y2²
(c)
x
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