2. Graphy = (x+ 2)(2 – x)(x² – 3x + 2) End Behavior: a. The leading term = , b. Degree of the leading term is EVEN ODD (choose one) c. Leading coefficient is POSITIVE NEGATIVE (choose one)
2. Graphy = (x+ 2)(2 – x)(x² – 3x + 2) End Behavior: a. The leading term = , b. Degree of the leading term is EVEN ODD (choose one) c. Leading coefficient is POSITIVE NEGATIVE (choose one)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Transcribed Image Text:**Polynomial Graphing Exercise**
### 2. Graphy = (x + 2)(2 – x)(x² – 3x + 2)
#### End Behavior:
a. The leading term = __________________________
b. Degree of the leading term is
- EVEN
- ODD
(choose one)
c. Leading coefficient is
- POSITIVE
- NEGATIVE
(choose one)
d. Based on my answers in parts b and c the end behavior of my polynomial is (choose one)
- DOWN-DOWN
- DOWN-UP
- UP-UP
- UP-DOWN
e. On a sketch the answer to part d looks like:
---
#### Zeros (or x-intercepts):
f. To find the zeros I set __________ and solve the equation: _________________________________
g. I need to factor the left side of my equation. Here is my work:
h. Fully factored form of my equations is _______________________________
i. Therefore the zeros and their multiplicities are:
---
#### Sketch:
Combining the end behavior and the information about the zeros, I sketch the graph:
---
**Note:** The worksheet involves determining the leading term, degree, coefficient sign, and exploring the impact on the graph's end behavior. It also guides you through factoring the equation to find zeros (x-intercepts) and their multiplicities, culminating in a graph sketch that integrates this information.
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