2. Given that z(1, 1) = 1 satisfies the equation 2(xp – yzg) = y² – x? where dz az p = and =Db ду find the values of y and z when x = through (1, 1). Answer: y = 0.702, z = 1.5 on the characteristic passing = 0.562
2. Given that z(1, 1) = 1 satisfies the equation 2(xp – yzg) = y² – x? where dz az p = and =Db ду find the values of y and z when x = through (1, 1). Answer: y = 0.702, z = 1.5 on the characteristic passing = 0.562
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![2 Given that z(1, 1) = 1 satisfies the equation
2(xp – yzg) = y² – a²
where
dz
p =
dz
and q =
dy
find the values of y and z when x =
through (1, 1).
Answer: y = 0.702, z =
1.5 on the characteristic passing](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1b244b27-5fe7-448e-ad05-f572f6877adf%2Ffb047e39-d91b-4bc4-8ad0-55e5ca6e0411%2Fjnrf7z5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2 Given that z(1, 1) = 1 satisfies the equation
2(xp – yzg) = y² – a²
where
dz
p =
dz
and q =
dy
find the values of y and z when x =
through (1, 1).
Answer: y = 0.702, z =
1.5 on the characteristic passing
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