2. Given that AABC A 87° 18⁰ 21° 42° 51º 3y 211 42 (5x+2) D

Q: C A If m/C = 90° while m/A=a and m/B = 3 in AABC, an expression representing the sum ( a+b sin a…

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Q: 2. Given tane = -√√3, 90° ≤ ≤ 180°, the exact value of sine can be written in the form √a b value of…

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Q: 5. In AABC, m2B = 90°. sin A = 2x + 1.5 and cos C = 3x – 0.9. Find x.

A: Given: In Triangle ABC∠B=90οsinA=2x+1.5cosC=3x−0.9x=?

Q: Given that ß = 101°, y = 24°, c = 15. Which of the following equations solves for a? a) a = (15 sin…

A: Given that the triangle we have to find choose the correct option

Q: 4. Find the general solution to the following trigonometric equation in degrees using the roster…

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Q: 11. Solve for x. C D 46° -1+8x 18x+5 B W -1=- +15 +1 14= t 12. Find the length between (-10,

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Q: Determine x. (Figure not drawn to scale.) 1.8 2.5 B x+3.5

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Q: d) 50°

A: Given problem:-

Q: a+vb So the value of a + b + c is. 4. If cos 36° A. 8 В. 10 С. 12 D. 15 Е. 18

A: Given PROBLEM:- cos(36°) =(a+√b)/c Find :- Value of a+b+c

Q: 18. If z₁ = 2 (cos 45° + i sin 45°) and z₂ = 4 (cos180° + i sin 180°), find: a. z₁z₂ and 21/22 in…

A: De Moivre's Theorem if rcosθ+isinθ is a complex number , then rcosθ+isinθn=rncosnθ+isinnθ

Q: Find the approximate value of csc 46° and sec 46°, given that sin 23° 0.3907.

A: We have to find out

Q: 3. Given that cose = 0, find all possible values of 0, for 0° <0< 360°. %3D

A: cosθ = 0 Value of cosθ is zero for odd multiples of π/2   cosθ = cos(2n +1)π/2 θ = (2n +1) π/2 , n =…

Q: Only need questions 8, 10 and 12

A: the yearly depreciation of company vehicles using the appraisal method.The appraisal method uses the…

Q: Given that z = 6(cos 90° + i sin 90°), then the following is true. z3 = (cos °+i sin + i =D+D; or…

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Q: 18. Given 0° < 0 < 360°, solve cos 0 = }. О з30° О з0°, 330° 60°, 300° O 300°

A: Given: cos θ=12, 0°≤θ≤360°

Q: 2 n ) Compute sin . An exact answer is required. 3

A: Answer and explanation is given below

Q: 1. Find one solution to: sec(33 + 10°) = csc(73 – 20°)

A: Given equation is We know that Therefore, by taking , we have