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2. GIVEN: Bdc = 250, Vin = 25 mA. Vpp Vac= +24Y 75K R C2 K zn3904 KL= ]OK2 す CI R2 HoouR てくND. FIG. 1-1A FOR THE NETWORK OF FIG. 1-1A , SHOWN ABOVE DTERMINE a) Vb = V base b) Ve = V emitter c) le =I emitter d) re = Rinput e) Rc = collector Resistance f) Av = Voltage gain el Vo = Vloltage out

2. GIVEN: Bdc = 250, Vin = 25 mA. Vpp Vac= +24Y 75K R C2 K zn3904 KL= ]OK2 す CI R2 HoouR てくND. FIG. 1-1A FOR THE NETWORK OF FIG. 1-1A , SHOWN ABOVE DTERMINE a) Vb = V base b) Ve = V emitter c) le =I emitter d) re = Rinput e) Rc = collector Resistance f) Av = Voltage gain el Vo = Vloltage out

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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2. GIVEN: Bdc = 250, Vin = 25 mA. Vpp |75K孝Ri K 2n3904 3RL= IOK2 CI RE=7K2 Hooup FIG. 1-1A FOR THE NETWORK OF FIG. 1-1A , SHOWN ABOVE DTERMINE a) Vb = V base b) Ve = V emitter c) le =I emitter d) re = Rinput e) Rc = collector Resistance f) Av = Voltage gain g) Vo = Voltage out
Transcribed Image Text:2. GIVEN: Bdc = 250, Vin = 25 mA. Vpp |75K孝Ri K 2n3904 3RL= IOK2 CI RE=7K2 Hooup FIG. 1-1A FOR THE NETWORK OF FIG. 1-1A , SHOWN ABOVE DTERMINE a) Vb = V base b) Ve = V emitter c) le =I emitter d) re = Rinput e) Rc = collector Resistance f) Av = Voltage gain g) Vo = Voltage out
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