2. Give the complete electron flow of the E2 reaction, be sure to clearly show the electrons that are flowing. Br + KBr LOK + CH3CH2CH2CH2OH

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Question 2

**Chapter 6, 7: Reaction Mechanisms and Electron Flow**

1. **S<sub>N</sub>2 Reaction**
   - **Reactants:** An alcohol (OK) and a bromoalkane.
   - **Solvent:** CH<sub>3</sub>CH<sub>2</sub>CH<sub>2</sub>CH<sub>2</sub>OH.
   - **Products:** An ether and KBr.
   - In this reaction, the nucleophile attacks the electrophilic carbon from the opposite side of the leaving group, resulting in the product where the attacking species is substituted for the leaving group (Br).

2. **E2 Reaction**
   - **Reactants:** An alcohol (OK) and a bromoalkane.
   - **Solvent:** CH<sub>3</sub>CH<sub>2</sub>CH<sub>2</sub>CH<sub>2</sub>OH.
   - **Products:** A double-bonded alkene, OH<sup>-</sup>, and KBr.
   - This reaction involves the elimination of the leaving group and a hydrogen on the adjacent carbon, leading to the formation of a double bond.

3. **S<sub>N</sub>1 Reaction**
   - **Reactants:** A bromoalkane.
   - **Solvent:** CH<sub>3</sub>CH<sub>2</sub>CH<sub>2</sub>CH<sub>2</sub>OH.
   - **Products:** An ether and C<sub>4</sub>H<sub>9</sub>Br.
   - The reaction proceeds by the formation of a carbocation intermediate, followed by the nucleophilic attack to form the final product.

4. **E1 Reaction**
   - **Reactants:** A bromoalkane.
   - **Solvent:** CH<sub>3</sub>CH<sub>2</sub>CH<sub>2</sub>CH<sub>2</sub>OH.
   - **Products:** A double-bonded alkene, water, and Br<sup>-</sup>.
   - The E1 reaction involves the formation of a carbocation intermediate followed by the removal of a proton to form a double bond.

**Diagrams:**
- Each reaction is depicted with arrows indicating the electron flow from nucleoph
Transcribed Image Text:**Chapter 6, 7: Reaction Mechanisms and Electron Flow** 1. **S<sub>N</sub>2 Reaction** - **Reactants:** An alcohol (OK) and a bromoalkane. - **Solvent:** CH<sub>3</sub>CH<sub>2</sub>CH<sub>2</sub>CH<sub>2</sub>OH. - **Products:** An ether and KBr. - In this reaction, the nucleophile attacks the electrophilic carbon from the opposite side of the leaving group, resulting in the product where the attacking species is substituted for the leaving group (Br). 2. **E2 Reaction** - **Reactants:** An alcohol (OK) and a bromoalkane. - **Solvent:** CH<sub>3</sub>CH<sub>2</sub>CH<sub>2</sub>CH<sub>2</sub>OH. - **Products:** A double-bonded alkene, OH<sup>-</sup>, and KBr. - This reaction involves the elimination of the leaving group and a hydrogen on the adjacent carbon, leading to the formation of a double bond. 3. **S<sub>N</sub>1 Reaction** - **Reactants:** A bromoalkane. - **Solvent:** CH<sub>3</sub>CH<sub>2</sub>CH<sub>2</sub>CH<sub>2</sub>OH. - **Products:** An ether and C<sub>4</sub>H<sub>9</sub>Br. - The reaction proceeds by the formation of a carbocation intermediate, followed by the nucleophilic attack to form the final product. 4. **E1 Reaction** - **Reactants:** A bromoalkane. - **Solvent:** CH<sub>3</sub>CH<sub>2</sub>CH<sub>2</sub>CH<sub>2</sub>OH. - **Products:** A double-bonded alkene, water, and Br<sup>-</sup>. - The E1 reaction involves the formation of a carbocation intermediate followed by the removal of a proton to form a double bond. **Diagrams:** - Each reaction is depicted with arrows indicating the electron flow from nucleoph
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