2. For what value(s) of h will y be in Span{v1, V2, V3} if 17 57 -3 -4 Vị = -1 V2 = -4 %3D V3 = 1 and %3D y : 3 %3D -2 -7 h

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I thought that a matrix spanned Rn if there was a pivot in every row. However, when a matrix is linearly dependent and the last row is made up of zeroes, it could still end up potentially spanning Rn. I'm a little bit confused about how that works because there isn't a pivot in every row in that situation. How does it still span when there's a free variable? For context, I'm looking at Practice Problem 2 in Section 1.3 of the Vector Equations notes in the textbook Linear Algebra and Its Applications, Fifth Edition by David C. Lay, Steven R. Lay, and Judi J. McDonald. If a picture should be needed, here it is.

ns in Linear Algebra
PRACTICE PROBLEMS
1. Prove that u +v = v + u for any u and v in R".
%3D
2. For what value(s) of h will y be in Span{v1, V2, V3} if
-3
-4
V1%3=
-1
-4
V3 =
and y =
%3D
y%3D
%3D
|
-2
-7
h
3. Let w1, w2, W3, u, and v be vectors in R". Suppose the vectors u and y are in
{W1, W2, W3}. Show that u + v is also in Span {w1, W2, w3}. [Hint: The soluti
Practice Problem 3 requires the use of the definition of the of a set of vec
It is useful to review this definition on Page 30 before starting this exercise.]
span
and u – 2v.
In Exercisan 0
Transcribed Image Text:ns in Linear Algebra PRACTICE PROBLEMS 1. Prove that u +v = v + u for any u and v in R". %3D 2. For what value(s) of h will y be in Span{v1, V2, V3} if -3 -4 V1%3= -1 -4 V3 = and y = %3D y%3D %3D | -2 -7 h 3. Let w1, w2, W3, u, and v be vectors in R". Suppose the vectors u and y are in {W1, W2, W3}. Show that u + v is also in Span {w1, W2, w3}. [Hint: The soluti Practice Problem 3 requires the use of the definition of the of a set of vec It is useful to review this definition on Page 30 before starting this exercise.] span and u – 2v. In Exercisan 0
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