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2. For the system shown below, determine an equivalent force and couple system at point C. 2000 lb 30° В 5 ft А C 2 ft Used with permission from "Engineering Mechanics: Statics," McGill/King, 4th Ed., 2003 O a. Equivalent Force = 1730å+1000ĝ lb Equivalent Moment = -6660k ft-lb b. Equivalent Force = 1000i+1730ĝ Ib %3D Equivalent Moment = -8460k ft-lb c. Equivalent Force = 1730å+10003 Ib Equivalent Moment = -10700k ft-lb d. None of the above

2. For the system shown below, determine an equivalent force and couple system at point C. 2000 lb 30° В 5 ft А C 2 ft Used with permission from "Engineering Mechanics: Statics," McGill/King, 4th Ed., 2003 O a. Equivalent Force = 1730å+1000ĝ lb Equivalent Moment = -6660k ft-lb b. Equivalent Force = 1000i+1730ĝ Ib %3D Equivalent Moment = -8460k ft-lb c. Equivalent Force = 1730å+10003 Ib Equivalent Moment = -10700k ft-lb d. None of the above

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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2. For the system shown below, determine an equivalent force and couple system at point C. 2000 lb 30° y 5 ft A C 2 ft Used with permission from "Engineering Mechanics: Statics," McGill/King, 4th Ed., 2003 a. Equivalent Force = 1730å+1000 Ib Equivalent Moment = -6660k ft-lb b. Equivalent Force = 1000å+1730; Ib Equivalent Moment = -8460k ft-lb c. Equivalent Force = 1730å+10003 lb Equivalent Moment = -10700k ft-Ib d. None of the above
Transcribed Image Text:2. For the system shown below, determine an equivalent force and couple system at point C. 2000 lb 30° y 5 ft A C 2 ft Used with permission from "Engineering Mechanics: Statics," McGill/King, 4th Ed., 2003 a. Equivalent Force = 1730å+1000 Ib Equivalent Moment = -6660k ft-lb b. Equivalent Force = 1000å+1730; Ib Equivalent Moment = -8460k ft-lb c. Equivalent Force = 1730å+10003 lb Equivalent Moment = -10700k ft-Ib d. None of the above
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