2. For the frame shown below, the radius of pulley is 0.5 m. a) Draw the free body diagram of the entire frame and of each member, including a diagram for the pulley. Show all forces, including the directions, if known. b) Determine the components of the reactions at A and E. Specify the direction (→, . 1, 4) for each. Ans: A, = 150 N, Ay = 250 N t, E 150 N, E, 450 N ↑ Im 3m 3m Im D. 2m E 700 N

Q: A. Determine the y component of reaction at A. B. Determine the x component of reaction at C. C.…

A: Given: w = 17 KN/m  Required: A. Determine the y component of reaction at A. B. Determine the x…

Q: Determine the force P required to maintain equilibrium of the pulley system, and the reactions at…

A: Draw the free body diagram of pulley 3. Equilibrium of vertical forces, ∑Fy=03T=1.25 kNT=0.417 kN

Q: Example: Determine the reactions on the beams A, B, and D. Neglect the weights of the members. A 300…

A:

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Q: A. Determine the x and y components of reaction at A. B. Determine the y component of reaction at B.

A: Given: F = 21 kN Free body diagram:

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A: Given above system of pully and W= 1.25kN

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A: Solve using slope deflection method: Fixed end moment: Span AB: MFAB=-wl212=-12×4212=-16…

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A:

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A: To find the vertical reaction at B

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A: Given W=1.25kN To find P=?

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A: The problem is based on equilibrium equations. We need to draw the FBD of the given system showing…

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Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.