2. For the following circuit, a. find a. b. find wo c. write a differential equation in i(t).

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### Electrical Circuits - LC Circuit Analysis

**Problem Statement:**
Consider the given circuit and solve the following:

a. Find \(\alpha\).
b. Find \(\omega_0\).
c. Write a differential equation in \(i(t)\).
d. Find the characteristic equation.
e. Find the roots of the characteristic equation.
f. Find the final value of current \(i(t)\) through the inductor.
g. Find current \(i(t)\) through the inductor for \(t \geq 0\) and plot \(i(t)\).
h. Find voltage \(v(t)\) for \(t \geq 0\) and plot \(v(t)\).

**Circuit Description:**
The circuit consists of the following components:
- A current source \(I_s = 15 \text{ mA}\),
- A resistor \(R = 1 \text{ k}\Omega\),
- An inductor \(L = 40 \text{ mH}\),
- A capacitor \(C = 50 \text{ nF}\),
- A voltage source \(V_0 = 2 \text{ V}\).

**Diagram:**

The circuit diagram is as follows:

1. A current source \(I_s = 15 \text{ mA}\) providing current to the leftmost branch.
2. The circuit then splits into two branches:
   - The first branch contains a resistor \(R = 1 \text{ k}\Omega\).
   - The second branch contains an inductor \(L = 40 \text{ mH}\).
3. These branches reconverge into a single node.
4. This node is connected to a capacitor \(C = 50 \text{ nF}\).
5. The capacitor is in parallel with a voltage source \(V_0 = 2 \text{ V}\)
6. The ground is connected to the return path of both the inductor and the capacitor + voltage source branch.

**Steps to Solve the Problem:**

1. **Finding \(\alpha\):**
   - \(\alpha = \frac{R}{2L}\)

2. **Finding \(\omega_0\):**
   - \(\omega_0 = \frac{1}{\sqrt{LC}}\)

3. **Writing the Differential Equation in \(i(t)\):**
   - Use Kirchhoff's Voltage Law (KVL) and Current Law
Transcribed Image Text:### Electrical Circuits - LC Circuit Analysis **Problem Statement:** Consider the given circuit and solve the following: a. Find \(\alpha\). b. Find \(\omega_0\). c. Write a differential equation in \(i(t)\). d. Find the characteristic equation. e. Find the roots of the characteristic equation. f. Find the final value of current \(i(t)\) through the inductor. g. Find current \(i(t)\) through the inductor for \(t \geq 0\) and plot \(i(t)\). h. Find voltage \(v(t)\) for \(t \geq 0\) and plot \(v(t)\). **Circuit Description:** The circuit consists of the following components: - A current source \(I_s = 15 \text{ mA}\), - A resistor \(R = 1 \text{ k}\Omega\), - An inductor \(L = 40 \text{ mH}\), - A capacitor \(C = 50 \text{ nF}\), - A voltage source \(V_0 = 2 \text{ V}\). **Diagram:** The circuit diagram is as follows: 1. A current source \(I_s = 15 \text{ mA}\) providing current to the leftmost branch. 2. The circuit then splits into two branches: - The first branch contains a resistor \(R = 1 \text{ k}\Omega\). - The second branch contains an inductor \(L = 40 \text{ mH}\). 3. These branches reconverge into a single node. 4. This node is connected to a capacitor \(C = 50 \text{ nF}\). 5. The capacitor is in parallel with a voltage source \(V_0 = 2 \text{ V}\) 6. The ground is connected to the return path of both the inductor and the capacitor + voltage source branch. **Steps to Solve the Problem:** 1. **Finding \(\alpha\):** - \(\alpha = \frac{R}{2L}\) 2. **Finding \(\omega_0\):** - \(\omega_0 = \frac{1}{\sqrt{LC}}\) 3. **Writing the Differential Equation in \(i(t)\):** - Use Kirchhoff's Voltage Law (KVL) and Current Law
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