### Problem Statement:2. For the beam shown, find the reactions at the supports and plot the shear-force and bending-moment diagrams. Label the diagrams properly and provide values at all key points.### Diagram Explanation:#### Left Diagram:- **Beam Description**: A simply supported beam with point loads. - **Supports**: - At point O (left end) on the \(y\)-axis, a reaction force \(R_1\) is acting upward. - At point C (right end), a reaction force \(R_2\) is acting upward.- **Loads**: - A 9 kN (kilo-Newton) point load acts downward at point A, which is 300 mm from point O. - A 15 kN point load acts downward at point B, which is 900 mm from point A and 300 mm from point C.- **Dimensions**: - From O to A: 300 mm. - From A to B: 900 mm. - From B to C: 300 mm.#### Right Diagram:- **Beam Description**: A simply supported beam with a point load and a uniformly distributed load.- **Supports**: - At point O (left end) on the \(y\)-axis. - At point C (right end).- **Loads**: - A 500 lbf (pound-force) point load acts downward at point A, which is 8 inches from point O. - A uniformly distributed load of 40 lbf/in acts downward between points B and C.- **Dimensions**: - From O to A: 8 inches. - From A to B: 6 inches. - From B to C: 6 inches.### Task Requirements:1. **Finding Reactions at Supports**: Calculate the reactions at the supports \(R_1\) and \(R_2\).2. **Shear Force Diagram (SFD)**: Construct the shear force diagram for the beam.3. **Bending Moment Diagram (BMD)**: Construct the bending moment diagram for the beam.4. **Labeling Diagrams**: Properly label the diagrams and indicate values at all significant points.This problem involves applying principles of static equilibrium and structural analysis to determine the reactions, shear forces, and moments in the beam structures.

Answered: Image /qna-images/answer/1c78a375-67f4-4311-8f51-2780461ee4eb.jpg

2. For the beam shown, find the reactions at the supports and plot the shear-force and bending- moment diagrams. Label the diagrams properly and provide values at all key points. y 19 kN |5 kN 500 Ibf 40 lbf/in 300 V 300 AC 900 A B A B C R1 |R2 8 in 6 in 6 in

2. For the beam shown, find the reactions at the supports and plot the shear-force and bending- moment diagrams. Label the diagrams properly and provide values at all key points. y 19 kN |5 kN 500 Ibf 40 lbf/in 300 V 300 AC 900 A B A B C R1 |R2 8 in 6 in 6 in

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

### Problem Statement:

2. For the beam shown, find the reactions at the supports and plot the shear-force and bending-moment diagrams. Label the diagrams properly and provide values at all key points.

### Diagram Explanation:

#### Left Diagram:

- **Beam Description**: A simply supported beam with point loads.
- **Supports**:
- At point O (left end) on the \(y\)-axis, a reaction force \(R_1\) is acting upward.
- At point C (right end), a reaction force \(R_2\) is acting upward.
- **Loads**:
- A 9 kN (kilo-Newton) point load acts downward at point A, which is 300 mm from point O.
- A 15 kN point load acts downward at point B, which is 900 mm from point A and 300 mm from point C.
- **Dimensions**:
- From O to A: 300 mm.
- From A to B: 900 mm.
- From B to C: 300 mm.

#### Right Diagram:

- **Beam Description**: A simply supported beam with a point load and a uniformly distributed load.
- **Supports**:
- At point O (left end) on the \(y\)-axis.
- At point C (right end).
- **Loads**:
- A 500 lbf (pound-force) point load acts downward at point A, which is 8 inches from point O.
- A uniformly distributed load of 40 lbf/in acts downward between points B and C.
- **Dimensions**:
- From O to A: 8 inches.
- From A to B: 6 inches.
- From B to C: 6 inches.

### Task Requirements:

1. **Finding Reactions at Supports**: Calculate the reactions at the supports \(R_1\) and \(R_2\).
2. **Shear Force Diagram (SFD)**: Construct the shear force diagram for the beam.
3. **Bending Moment Diagram (BMD)**: Construct the bending moment diagram for the beam.
4. **Labeling Diagrams**: Properly label the diagrams and indicate values at all significant points.

This problem involves applying principles of static equilibrium and structural analysis to determine the reactions, shear forces, and moments in the beam structures.

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