**Problem Statement:**2. For the beam and loading shown below, a) Draw the shear and bending moment diagrams. b) Determine the maximum absolute values of the shear and bending moment.(Intermediate Answers: \( C_y = 2P \) (↑), \( M_C = 3Pa \) (into page); Final Answers: \(|V_{\text{max}}| = 2P\), \(|M_{\text{max}}| = 3Pa\))**Diagram Description:**- A horizontal beam labeled \( AB \) is subjected to loading conditions.- The beam is fixed at point \( C \) and experiences two equal forces, \( P \), acting downwards at points \( A \) and \( B \).- The distance between points \( A \) and \( B \) is \( a \), and the distance from \( A \) to the fixed point \( C \) is \( 2a \).**Diagrams:**- **Shear Force Diagram:** - Expect a step change at both points \( A \) and \( B \) due to the applied forces. - The diagram will show horizontal lines with changes at points where the forces act.- **Bending Moment Diagram:** - The bending moment will start from zero at point \( C \) and show a curve that peaks between \( B \) and the fixed support. - The maximum moments occur at point \( B \).**Calculations:**- **Shear Force (\( V \)):** - Maximum absolute shear force \(|V_{\text{max}}| = 2P\)- **Bending Moment (\( M \)):** - Maximum absolute bending moment \(|M_{\text{max}}| = 3Pa\)The analysis involves resolving forces and moments with conditions such as equilibrium in vertical and rotational movement, applying static equilibrium equations to solve for reactions, and then plotting the respective diagrams.

Answered: Image /qna-images/answer/4977c9a6-7689-4ad4-8b92-b94ade428b9a.jpg

2. For the beam and loading shown below, a) Draw the shear and bending moment diagrams, b) Determine the maximum absolute values of the shear and bending moment. (Intermediate Ans: Cy = 2P (↑), Mc = 3Pa (into page); Ans: IVmaxl = 2P , IMmaxl = 3Pa ) A В a a

2. For the beam and loading shown below, a) Draw the shear and bending moment diagrams, b) Determine the maximum absolute values of the shear and bending moment. (Intermediate Ans: Cy = 2P (↑), Mc = 3Pa (into page); Ans: IVmaxl = 2P , IMmaxl = 3Pa ) A В a a

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Bending Moment

In general, we can define the bending moment as the reaction induced when a certain amount of load or force is applied to an element which makes it bend.

Question

100%

**Problem Statement:**

2. For the beam and loading shown below,

a) Draw the shear and bending moment diagrams.
b) Determine the maximum absolute values of the shear and bending moment.

(Intermediate Answers: \( C_y = 2P \) (↑), \( M_C = 3Pa \) (into page);
Final Answers: \(|V_{\text{max}}| = 2P\), \(|M_{\text{max}}| = 3Pa\))

**Diagram Description:**

- A horizontal beam labeled \( AB \) is subjected to loading conditions.
- The beam is fixed at point \( C \) and experiences two equal forces, \( P \), acting downwards at points \( A \) and \( B \).
- The distance between points \( A \) and \( B \) is \( a \), and the distance from \( A \) to the fixed point \( C \) is \( 2a \).

**Diagrams:**

- **Shear Force Diagram:**
- Expect a step change at both points \( A \) and \( B \) due to the applied forces.
- The diagram will show horizontal lines with changes at points where the forces act.

- **Bending Moment Diagram:**
- The bending moment will start from zero at point \( C \) and show a curve that peaks between \( B \) and the fixed support.
- The maximum moments occur at point \( B \).

**Calculations:**

- **Shear Force (\( V \)):**
- Maximum absolute shear force \(|V_{\text{max}}| = 2P\)

- **Bending Moment (\( M \)):**
- Maximum absolute bending moment \(|M_{\text{max}}| = 3Pa\)

The analysis involves resolving forces and moments with conditions such as equilibrium in vertical and rotational movement, applying static equilibrium equations to solve for reactions, and then plotting the respective diagrams.

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