2. For a liability coverage: (i) Losses per insured follow an exponential distribution with mean . (ii) A follows an exponential distribution with mean 0.002. Calculate the probability that a randomly selected loss exceeds 2000.

Q: 2/18 – 12/32 + 3V50

A: The solution is given below in the next step:

Q: 7+3.5-11

A: Let's Solve,

Q: 5(18)

A: To find5(18)

Q: 6.4 3

A:

Q: 5/14+1/6

A: 514+16=15+742

Q: expand (a-b)7

A: The solution is given in the next step.

Q: sing the geometry of the graph ,evalvate the definite integrals.

A: As this is a multiple subpart question according to the Bartleby Answering rule, only first three…

Q: A 2/15 B 30 V35 5 20

A: Given,  A circle with secant and tangent  We have to find the value of x

Q: 3/8+5/24

A: The given expression is 3/8 + 5/24.Simplify the given expression as follows.

Q: 3. Identify all the cycles at each node of the directed graph above.

A: Cycle is defined as a path that start and end at the same vertex.

Q: d. 1 3a+18 = 1 - 8 a+6

A:

Q: (n + 4)3 =

A: Given query is to expand (n+4)3

Q: 12 16

A: We know that If a perpendicular is drawn from the vertex of right angle triangle of a right triangle…