2. Find the volume of the solid lying under the elliptic x2 paraboloid + 4 y2 +z = 1 and above the rectangle 9 R = [0, 4] × [-1, 4].

Q: Find the area of the “triangular” region in the xy-plane that is bounded on the right by the…

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Q: Consider the area bounded by the curves y = 4x³ - x² - 14x and y = x²+2x. Where do the curves…

A: Step 1:Step 2:I hope it is clear if there is any doubt, please ask in clarification section.

Q: Find the area of the part of the hyperbolic araboloid z = y² – x² nat lies between the cylinders x²…

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Q: Let R be the rectangular region with (1,2) , (2,3) , (3,2) and (2,1) as corners. Use change of…

A: Changing the variables

Q: 1.) Find the area bounded by the regions given by the graphs of y 3x2-10x and y x2+2x. Make sure you…

A: There are multiple unrelated questions. I will address the first one.The curves are:y = f(x) = 3x3 -…

Q: Q6/ Find the volume of the parallclogram-sided determined by: u- -3i +7j +5k, v -3i + 7j-3k, and w-…

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Q: Find the surface area of the portion of the half ball with radius a which cuts off by the cylinder…

A: The equation of a ball with radius a is x2+y2+z2=a2. The surface area of the function z=fx,y over…

Q: Find the surface area of the portion of the half ball with radius which cuts off by the cylinder x2…

A: Concept: The surface area of the half ball is given by: A=∬1+∂z∂y2+∂z∂x2dA Where ∂z∂y, ∂z∂x is the…

Q: Compute the volume of the column with a square base R= {(x,y): |x|< 3, |y| <3} cut by the plane z =…

A: We have to find volume whose base is square-

Q: Which is the equation of a sphere with a center at (1,0,-2) with a volume of 36(pi)(u^3)? a.…

A: We first defined the equation of sphere and centre,volume . Using this formula we have equation (a)…

Q: Compute for the volume of the solid formed bounded by the equations (y- 4)2 = x - 3, x-10, y-4, and…

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Q: Show that the volume of the segment cut from the paraboloid x2 /a2 + y2/ b2 = z/ c by the plane z =…

A: Show that the volume of the segment cut from the paraboloidX^2 /a^2 + y^2/ b^2 = z/ cby the plane z…