2. Find the smaller angle between A = 10ay + 2ax and B = -4ay+ 0.5az.
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- =43π7×1083×3×10-7= How is this solved?II. State whether each of the following measurements are reported correctly or incorrectly. 5) 75.5 + 0.6 6) 10.12 + 3.35 7) 9+1 8) 273 + 0.7 9) 273 + 0.75 10) 273.01 ± 110 mL 9 24 mL 8 mL 7 Measuring Тool 25 mL 7 mL Volume, mass and/or length measurement (with units) Measuring Тol 8 cm 9 cm Volume, mass and/or length measurement (with units) Page 13 of 14
- 2. Significant Figures (a) Express the numbers listed in Data Table 3 to three significant figures, writing the numbers in the first column in normal notation and the numbers in the second column in powers of 10 (scientific) notation. 25 Copyright 2015 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s). Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it. EXPERIMENT 2 Experimental Uncertainty (Error) and Data Analysis DATA TABLE 3 Purpose: To practice expressing significant figures. 0.524 15.08 1444 0.0254 83,909 5280 0.060 82.453 0.00010 (continued) 2,700,000,000 Laboratory Reportthe answer i got was 1.283 n.m using 1*5.00* 83.426*3.07*10^-3 but it wasn’t a correct answer8. Angel Locsin is 155meters away from the center of a snow mountain. Angel is 1.5 meters Tall and forms an angle of elevation of 66.02º when she is looking at the tip of the Mountain from her location. How tall is the mountain? ock iStock iStock Imagos ck ock istock Stock
- Questions are in the picture.6. Atoms of a certain element have a diameter of 108 cm. Given 1 km = 1,000 m and 1 m = 100 cm, about how many of these atoms can be fit along a line with a 1 Astronomical Unit length?3. Solve to the significant number of digits (a) 25.3456 + 888.010 + 53.11 +7-1.0 (b) (45.805*2.00)/5.0 + 0.1