2. Find the limit using Squeeze theorem 1 lim-2|x – 2| sin( r - 2

Q: 3 Use the Squeeze Theorem to evaluate lim f(x), where f(x)=x²cos (-). x A B C D - 0 0 1 8 -0-x

A:

Q: (2) Use the definition of limit of a function to find lim x³-3x-2 x+2x2 - 3x+2

A: To find the limit of the function x3−3x−2x2−3x+2 as x approaches 2, it can apply the definition of…

Q: Let the function f: DCR R be defined by f(x) = lim n0 2+ " (a) Evaluate lim,+-1- f(x) and lim,-1+…

A: The given function is  fx=limn→∞xn2+xn

Q: Show that the limit does not exist: (x - 1)(y-2)² lim (x,y)→(1,2) (x − 1)² + 5(y − 2)4* -

A: Given, lim(x, y)→(1, 2)(x-1)(y-2)2(x-1)2+5(y-2)4

Q: V6 - 5x , x > -1 Determine lim x-2 wheref ( x %3D 2x2 - 5x , x < -1

A:

Q: f(8 + h) – f(8) lim h-0 h where f(x) = 6x + 2. If the limit does not exist enter DNE. Limit =

A:

Q: Find the limit lim h→0 lim h→0 f(−9 + h) — f(−9) h f(-9+h)-f(-9) h if f(x) = 829 - 6x².

A: To find the limit , if .

Q: Q/Calculate limit statement lim sinx-cost XT 4 1-4

A:

Q: 1. (a) Evaluate the limit or state that it does not exist: i. lim 32-1 37-1 ii. lim V1+r-VI-x (b)…

A: The limits are required to be solved. Each part is solved in detail below.

Q: f(x)=X÷2x if x 23 3x ifx<3

A:

Limits of Multivariable Functions

Multivariable calculus is an extension of single variable calculus. It involves several variables instead of just one. Assume there is an open set containing points (x0, y0), let f be a function defined in that open interval except for the points (x0, y0). The multivariable limit of this function as it approaches the points (x0, y0) and is denoted as: