2. Find the general solution. a) a' = -(2/t)x+t. b) y'+y=e². c) x² + 2tx=e-t² 1. First-Order Differential Equ d) tx' = -x + t². e) 0' = -a0 + exp(bt). f) (t² +1)x² = −3tx+6t.

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