2. Find the Fourier integral of the given function and discuss it at the discontinuity points π.χ 2 1-x² f(x) = COS X, |x | < 1/1/2 |x /> 1/1/2/2 and then find COS dx

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A: Note:-  cosA-B =cos A cos B - sin A sin BsinA+B =sin A cos B + cos A sin B   Part (1):- Given that…

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A: W(π/4) = -sin(π/2) = -1 W(π/6) = -sin(π/3) = - √3/2 Since, Wronskian is not zero for a single value…

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A: answer = -2sin2t   explanation is given in the below step

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A: We will solve the following.

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A: given  f(x)=8sinx d dx(sinx)=cosxstandard form of quation is y-y1=m(x-x1)where m is slope m=f'(x)

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