2. Find the absolute maximum and minimum values of f(x)= x³ – 3x +1 over the interval [0, 3].

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**2. Find the absolute maximum and minimum values of \( f(x) = x^3 - 3x + 1 \) over the interval \([0, 3]\).**

To solve this problem, we need to evaluate the function \( f(x) = x^3 - 3x + 1 \) at critical points and endpoints within the given interval \([0, 3]\). Critical points occur where the derivative \( f'(x) = 0 \) or where the derivative does not exist. In this case:

1. Calculate the derivative: \( f'(x) = 3x^2 - 3 \).
2. Set the derivative equal to zero to find critical points: \( 3x^2 - 3 = 0 \Rightarrow x^2 = 1 \Rightarrow x = \pm 1 \).

Since \( x = -1 \) does not lie within the interval \([0, 3]\), consider only \( x = 1 \).

3. Evaluate \( f(x) \) at the critical point and endpoints:
   - \( f(0) = 0^3 - 3(0) + 1 = 1 \)
   - \( f(1) = 1^3 - 3(1) + 1 = -1 \)
   - \( f(3) = 3^3 - 3(3) + 1 = 19 \)

4. Compare the values to determine the absolute maximum and minimum:
   - Absolute Minimum: \( f(1) = -1 \)
   - Absolute Maximum: \( f(3) = 19 \)

Thus, the absolute minimum value of \( f(x) \) on the interval \([0, 3]\) is \(-1\), and the absolute maximum value is \(19\).
Transcribed Image Text:**2. Find the absolute maximum and minimum values of \( f(x) = x^3 - 3x + 1 \) over the interval \([0, 3]\).** To solve this problem, we need to evaluate the function \( f(x) = x^3 - 3x + 1 \) at critical points and endpoints within the given interval \([0, 3]\). Critical points occur where the derivative \( f'(x) = 0 \) or where the derivative does not exist. In this case: 1. Calculate the derivative: \( f'(x) = 3x^2 - 3 \). 2. Set the derivative equal to zero to find critical points: \( 3x^2 - 3 = 0 \Rightarrow x^2 = 1 \Rightarrow x = \pm 1 \). Since \( x = -1 \) does not lie within the interval \([0, 3]\), consider only \( x = 1 \). 3. Evaluate \( f(x) \) at the critical point and endpoints: - \( f(0) = 0^3 - 3(0) + 1 = 1 \) - \( f(1) = 1^3 - 3(1) + 1 = -1 \) - \( f(3) = 3^3 - 3(3) + 1 = 19 \) 4. Compare the values to determine the absolute maximum and minimum: - Absolute Minimum: \( f(1) = -1 \) - Absolute Maximum: \( f(3) = 19 \) Thus, the absolute minimum value of \( f(x) \) on the interval \([0, 3]\) is \(-1\), and the absolute maximum value is \(19\).
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