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2. Find output voltage and current for a binary-weighted resistor DAC of 4 bits with given condition of R = 1kº, Rf = 5kN, VR = -12v and applied binary word is 1101. (2 it 3. Find the voltage for an R-2 DAC ui 4 bits with given condition of R = 6kn,

2. Find output voltage and current for a binary-weighted resistor DAC of 4 bits with given condition of R = 1kº, Rf = 5kN, VR = -12v and applied binary word is 1101. (2 it 3. Find the voltage for an R-2 DAC ui 4 bits with given condition of R = 6kn,

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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2. Find output voltage and current for a binary-weighted resistor DAC of 4 bits with given condition of R = 1km, Rf = 5kn, VR = -12v and applied binary word is 1101. (2 3. Find the voltage for an R-2 AC U 4 bits with given condition of R = 6kN, UI
Transcribed Image Text:2. Find output voltage and current for a binary-weighted resistor DAC of 4 bits with given condition of R = 1km, Rf = 5kn, VR = -12v and applied binary word is 1101. (2 3. Find the voltage for an R-2 AC U 4 bits with given condition of R = 6kN, UI
Weighted Sum DAC One way to achieve D/A conversion is to use a summing amplifier. This approach is not satisfactory for many bits because it requires too much precision in the summing resistors. Inputs are weighted in the summing amplifier to produce the corresponding analog voltage N O O O O Wherein: ■ · ■ ■ . · bi 10 = VR2(t-1) R i=1 Vo = -Rflo N-number of bits lo-Current output Vo-Voltage output VR - Reference voltage R- Fixed Resistor R- Junction Resistor bi - Digital equivalent lo Voltage output Vo: = 1 1 0 1 Example: Find output voltage and current for a binary-weighted resistor DAC of 4 bits with the given condition of R = 10kn, R = 5k, VR = -10v and applied binary word is 1001. Current output la: Vo = R4 -10v 0 0 1 1 Ω [20 × 10kΩ 21 × 10kΩ 22 × 10kΩ 23 × 10kΩΙ + + + -Rflo R3 √₂ = (10kn x -0.001125 A) = 5.625v = -0.001125 A Vout
Transcribed Image Text:Weighted Sum DAC One way to achieve D/A conversion is to use a summing amplifier. This approach is not satisfactory for many bits because it requires too much precision in the summing resistors. Inputs are weighted in the summing amplifier to produce the corresponding analog voltage N O O O O Wherein: ■ · ■ ■ . · bi 10 = VR2(t-1) R i=1 Vo = -Rflo N-number of bits lo-Current output Vo-Voltage output VR - Reference voltage R- Fixed Resistor R- Junction Resistor bi - Digital equivalent lo Voltage output Vo: = 1 1 0 1 Example: Find output voltage and current for a binary-weighted resistor DAC of 4 bits with the given condition of R = 10kn, R = 5k, VR = -10v and applied binary word is 1001. Current output la: Vo = R4 -10v 0 0 1 1 Ω [20 × 10kΩ 21 × 10kΩ 22 × 10kΩ 23 × 10kΩΙ + + + -Rflo R3 √₂ = (10kn x -0.001125 A) = 5.625v = -0.001125 A Vout
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