2. Find out the gross sectional area of a tension member with the following data : Fy = 50 Ksi, Fu=65 Ksi, Dead load = 120 K Live load = 150 K. The section has 4 bolts of% in diameter. Use only LRFD approach.

Structural Analysis
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Chapter2: Loads On Structures
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Problem 2
1. Determine the LRFD design tensile strength and ASD allowable design tensile strength
W14x132 section. Assume Fy
equivant area) =0.85. You need not consider block shear effect.
50 Ksi, Fu=65 Ksi, Ag = 38.8 in, U (conversion factor fc
2. Find out the gross sectional area of a tension member with the following data
Fy = 50 Ksi, Fu=65 Ksi, Dead load = 120 K Live load = 150 K. The section has 4 bolts of% in
diameter. Use only LRFD approach.
%3D
3. Determine the compressive load carrying capacity (both LRFD and ASD) for a W14x176 section
using the following given table of AISC manual (Page 2) The column has overall length of 20 ft ar
fixed at both ends.
All the following figures are relevant to problem 3.
TABLE 5.1
Approximate Values of Effective Length Factor, K
(a)
(b)
(c)
(d)
Buckled shape of column
is shown by dashed line
Theoretical K yaluc
05
07
Transcribed Image Text:1. Determine the LRFD design tensile strength and ASD allowable design tensile strength W14x132 section. Assume Fy equivant area) =0.85. You need not consider block shear effect. 50 Ksi, Fu=65 Ksi, Ag = 38.8 in, U (conversion factor fc 2. Find out the gross sectional area of a tension member with the following data Fy = 50 Ksi, Fu=65 Ksi, Dead load = 120 K Live load = 150 K. The section has 4 bolts of% in diameter. Use only LRFD approach. %3D 3. Determine the compressive load carrying capacity (both LRFD and ASD) for a W14x176 section using the following given table of AISC manual (Page 2) The column has overall length of 20 ft ar fixed at both ends. All the following figures are relevant to problem 3. TABLE 5.1 Approximate Values of Effective Length Factor, K (a) (b) (c) (d) Buckled shape of column is shown by dashed line Theoretical K yaluc 05 07
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