2. Ethylene burns in oxygen to form carbon dioxide and water vapor: C2HA(g) + 3 O2(g) → 2 CO2(g) + 2 H2O(g) How many liters of water can be formed if 1.25 liters of ethene are consumed in this reaction?

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### Combustion of Ethylene

#### Reaction Overview
Ethyene burns in oxygen to form carbon dioxide and water vapor:

\[ \text{C}_2\text{H}_{4(g)} + 3 \text{O}_{2(g)} \rightarrow 2 \text{CO}_{2(g)} + 2 \text{H}_2\text{O}_{(g)} \]

#### Problem Statement
How many liters of water can be formed if 1.25 liters of ethene are consumed in this reaction?

---

This chemical equation represents the combustion of ethylene (\( \text{C}_2\text{H}_4 \)) in oxygen, forming carbon dioxide (\( \text{CO}_2 \)) and water vapor (\( \text{H}_2\text{O} \)). According to the stoichiometry of the balanced equation, 1 mole of ethene reacts with 3 moles of oxygen to produce 2 moles each of carbon dioxide and water vapor. 

By using the ideal gas law assumptions and the stoichiometry of the reaction, you can determine the volume of water vapor produced from a given volume of ethene under the same conditions of temperature and pressure.
Transcribed Image Text:### Combustion of Ethylene #### Reaction Overview Ethyene burns in oxygen to form carbon dioxide and water vapor: \[ \text{C}_2\text{H}_{4(g)} + 3 \text{O}_{2(g)} \rightarrow 2 \text{CO}_{2(g)} + 2 \text{H}_2\text{O}_{(g)} \] #### Problem Statement How many liters of water can be formed if 1.25 liters of ethene are consumed in this reaction? --- This chemical equation represents the combustion of ethylene (\( \text{C}_2\text{H}_4 \)) in oxygen, forming carbon dioxide (\( \text{CO}_2 \)) and water vapor (\( \text{H}_2\text{O} \)). According to the stoichiometry of the balanced equation, 1 mole of ethene reacts with 3 moles of oxygen to produce 2 moles each of carbon dioxide and water vapor. By using the ideal gas law assumptions and the stoichiometry of the reaction, you can determine the volume of water vapor produced from a given volume of ethene under the same conditions of temperature and pressure.
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