**Estimating the Mean and Standard Deviation from a Dotplot****Question 2:**Estimate the mean and standard deviation of the dotplot below based on a sample with n=360. For the standard deviation, use the 95% rule and show the calculation of your estimate.**Dotplot Description:**- The dotplot presents data values on the x-axis ranging from 40 to 100.- The distribution appears symmetric with a peak around 65-75.- The number of dots (representing data points) increases gradually up to the range 65-75 and then decreases symmetrically. The goal is to provide the following information:- Mean: ________________- Center 95% interval from: ___________ to: _______________- Standard deviation: __________________**Graph Explanation:**- The x-axis is labeled with values starting from 40 to 100, representing the sample data points.- The y-axis does not have specific labels but shows the frequency of each data point.- Most data points are concentrated around 60-80, indicating this range hosts the majority of the data.- Outliers are visible on both the low (less than 50) and high ends (more than 90) depicting fewer data occurrences.When prompted to estimate the mean, standard deviation, and the 95% interval from this dotplot information, guide the students to:- Visually assess the center of the distribution (for the mean).- Identify the middle 95% of the data points for the interval.- Use the 95% rule (considering that approximately 95% of the data lies within two standard deviations of the mean) to estimate the standard deviation.In this case, educators can assist students in determining these values contextually based on the dotplot representation provided.

Sample size n=360The objective is to estimate the mean and standard deviation.

Answered: 2. Estimate the mean and standard…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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2. Estimate the mean and standard deviation of the dotplot below based on a sample with n=360. For standard deviation, use the 95% rule and show the calculation of your estimate. 40 50 60 70 80 h... 90 100 Mean: Center 95% interval from: Standard deviation: to: