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2. DMS 1.03 CH₂OH 1.03 2. (CH3)2S Br2 KMnO4, NaOH 20 1 2 ΤΗ Pd or Pt (catalyst) HBr HBr ROOR (peroxide) H₂O H₂SO HCL cold 18 17 5 HI 16 15 mCPBA 14 1. BHI 2. H₂C Br 13 12 11 10 9 OsO4 Br2 H

2. DMS 1.03 CH₂OH 1.03 2. (CH3)2S Br2 KMnO4, NaOH 20 1 2 ΤΗ Pd or Pt (catalyst) HBr HBr ROOR (peroxide) H₂O H₂SO HCL cold 18 17 5 HI 16 15 mCPBA 14 1. BHI 2. H₂C Br 13 12 11 10 9 OsO4 Br2 H

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question 1 Please predict the products for each of the following reactions. Clearly show the regiochemistry (Markovnikov vs anti-Markovnikov) and stereochemistry (syn- vs anti- or both). If a mixture of enantiomers is formed, please draw all the enantiomers. Hint: In this case you must choose the best answer to demonstrate the stereochemistry of H2 addition. Pd or Pt (catalyst) 20 1 2 HBr ROOR (peroxide) H₂O H₂SO4 18 HCI 17 5 16 15 1. BH3.THF 14 2. H₂O2, NaOH 8 13 12 11 10 Br2 Br2 CH₂OH 1.03 2. DMS KMnO4, NaOH cold HI MCPBA 1. OsO4 2. H₂O₂ CH.COSH (peroxyacid) MCPBA A B а A B C Pd or Ni (catalyst) D₂ (deuterium) Br2 H₂O BH3⚫THF Br₂ 'H 8.8 'H D
Transcribed Image Text:Question 1 Please predict the products for each of the following reactions. Clearly show the regiochemistry (Markovnikov vs anti-Markovnikov) and stereochemistry (syn- vs anti- or both). If a mixture of enantiomers is formed, please draw all the enantiomers. Hint: In this case you must choose the best answer to demonstrate the stereochemistry of H2 addition. Pd or Pt (catalyst) 20 1 2 HBr ROOR (peroxide) H₂O H₂SO4 18 HCI 17 5 16 15 1. BH3.THF 14 2. H₂O2, NaOH 8 13 12 11 10 Br2 Br2 CH₂OH 1.03 2. DMS KMnO4, NaOH cold HI MCPBA 1. OsO4 2. H₂O₂ CH.COSH (peroxyacid) MCPBA A B а A B C Pd or Ni (catalyst) D₂ (deuterium) Br2 H₂O BH3⚫THF Br₂ 'H 8.8 'H D
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