2. Determine the equation (in factored form) for a quadratic function with roots 3 +3/2 and a y intercept of 18. Show all your steps. No decimals. y=a (x-3+ 3J5)(×-3-3E) 18= a (0-3+ 3J2) (0-3-3J2) 18=a(-3+3J2)(-3-352) 18= 3-6J2 a 18=a 3-6J2 6+12/2=a [4 marks] 6+/2 J2 (3-313J3)(x-3-3E)
2. Determine the equation (in factored form) for a quadratic function with roots 3 +3/2 and a y intercept of 18. Show all your steps. No decimals. y=a (x-3+ 3J5)(×-3-3E) 18= a (0-3+ 3J2) (0-3-3J2) 18=a(-3+3J2)(-3-352) 18= 3-6J2 a 18=a 3-6J2 6+12/2=a [4 marks] 6+/2 J2 (3-313J3)(x-3-3E)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Vertex: ( 3, -4)
f(3)=(7-3)(7-4)
vertex: (3:-)
2. Determine the equation (in factored form) for a quadratic function with roots 3 ± 3/2 and a y
intercept of 18. Show all your steps. No decimals.
[4 marks]
y=a (x-3+ 3J2)(-3-3E)
18= a (0-3+3J5)(0-3-3J2)
18=a(-3+3J2)(-3-352)
18= 3-6J2 a
18= a
3-6J2
6+12/2 =a
6+/2 JZ
(3-3+3J2)(x-3-3J2)
i 9 = -
to Sap](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb66ae794-c54c-47d1-a8fa-13525ab54b01%2F7b3d882c-32ee-422a-a91c-3ff9849d2198%2F1rq0vk8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Vertex: ( 3, -4)
f(3)=(7-3)(7-4)
vertex: (3:-)
2. Determine the equation (in factored form) for a quadratic function with roots 3 ± 3/2 and a y
intercept of 18. Show all your steps. No decimals.
[4 marks]
y=a (x-3+ 3J2)(-3-3E)
18= a (0-3+3J5)(0-3-3J2)
18=a(-3+3J2)(-3-352)
18= 3-6J2 a
18= a
3-6J2
6+12/2 =a
6+/2 JZ
(3-3+3J2)(x-3-3J2)
i 9 = -
to Sap
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