2. Determine the design strength P of an A992 W18x50 connected by bolts on plates on both flanges as shown in the figure. Bolts are 1/2-inch diameter on standard holes. Use case 2 for the shear lag factor. te: For the shear lag factor, imagine the section as two WT-sections, each with half the nominal depth and half the linear weight of the W-section. The ance of the top most part of the flange of the WT-section from the centroid of the WT-section is the value of x.) 4 in 4 in 1.8 in W18x50

2. Determine the design strength P of an A992 W18x50 connected by bolts on plates on both flanges as shown in the figure. Bolts are 1/2-inch diameter on standard holes. Use case 2 for the shear lag factor. te: For the shear lag factor, imagine the section as two WT-sections, each with half the nominal depth and half the linear weight of the W-section. The ance of the top most part of the flange of the WT-section from the centroid of the WT-section is the value of x.) 4 in 4 in 1.8 in W18x50

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter3: Tension Members

Section: Chapter Questions

Problem 3.3.2P

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1 please with explanation
A plate with width of 420 mm and thickness of 13 mm is to be connected to a plate of the same width and thickness by 30 mm diameter bolts, as shown in the Figure 1. The holes are 3mm larger than the bolt diameter. The plate is A36 steel with yield strength Fy = 248MPa. Assume allowable tensile stress on net area is 0.60Fy. It is required to determine the value of b such that the net width along bolts 1-2-3-4 is equl to the net width along bolts 1-2-4. W = 420 mm t = 13 mm a = 64 mm c = 104 mm d = 195 mm Bolt Diameter = 30 mm Holes Diameter = 30 mm + 3 = 33 mm ?? = 248 MPa Allowable Tensile Stress on ?? = 0.60Fy a. Calculate the vaue of b in millimeters. b. Calculate the value of the net area for tension in plates in square millimeters. c. Calculate the value of P so that the allowable tensile stress on net area will not be exceeded.
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WideFlange Section: W 16x67
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STEEL ANALYSIS full solution and final answer to 4 decimal places pls
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