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2. Design the beam that shown in the Figure below for shear (determine the stirrups spacing) for each of the following Vu value: 1. Vu=55 kN. 2. Vu= 100 kN. 3. Vu = 260 kN. Assume that the designer intends to use: A width of 350 mm and an effective depth of 610 mm. Concrete of fc' = 21 MPa. Steel of fyt = 413 MPa. Stirrups of 10 mm diameter (Abar = 71 mm2). Normal weight concrete. %3D 610mm 700mm 350mm

2. Design the beam that shown in the Figure below for shear (determine the stirrups spacing) for each of the following Vu value: 1. Vu=55 kN. 2. Vu= 100 kN. 3. Vu = 260 kN. Assume that the designer intends to use: A width of 350 mm and an effective depth of 610 mm. Concrete of fc' = 21 MPa. Steel of fyt = 413 MPa. Stirrups of 10 mm diameter (Abar = 71 mm2). Normal weight concrete. %3D 610mm 700mm 350mm

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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2. Design the beam that shown in the Figure below for shear (determine the stirrups spacing) for each of the following Vu value: 1. Vu = 55 kN. %3D 2. Vu = 100 kN. 3. Vu = 260 kN. %3D Assume that the designer intends to use: A width of 350 mm and an effective depth of 610 mm. Concrete of fc' = 21 MPa. Steel of fyt =413 MPa. Stirrups of 10 mm diameter (Abar = 71 mm?). Normal weight concrete. %3D 610mm 700mm 350mm
Transcribed Image Text:2. Design the beam that shown in the Figure below for shear (determine the stirrups spacing) for each of the following Vu value: 1. Vu = 55 kN. %3D 2. Vu = 100 kN. 3. Vu = 260 kN. %3D Assume that the designer intends to use: A width of 350 mm and an effective depth of 610 mm. Concrete of fc' = 21 MPa. Steel of fyt =413 MPa. Stirrups of 10 mm diameter (Abar = 71 mm?). Normal weight concrete. %3D 610mm 700mm 350mm
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