2. Demonstrate that Pv (QAR) and (PVQ)^R are not logically equivalent, by giving a situation where they have different truth values.

Q: 5x-24+x2

A: Rearrange the given expression.

Q: T+4 dx 620.18 %3D 2.

A: Given that: ∫25x5+4xdx

Q: -2d+1=9

A:

Q: 3y = -x+6 %3D 2x + 4y = 12

A:

Q: dr a 2 1 +3

A:

Q: 23-8K

A:

Q: x=7, x2-2x+5=

A:

Q: TC 3X-X²

A:

Q: (2-3x)²

A:

Q: Evaluate x2 + 5x, for x = 6.

A: x2+5x, x=6

Q: find domain

A: If you have any questions let me know in comment box thankyou for your question.

Q: 2x-14

A:

Q: 2x + 1 = 98

A: Given 2x+1 = 98

Q: 2: Find: L-1[: 1 3 - 3]

A:

Q: x2-8x-7=0

A: solve the following equation

Q: x2-16x-18=0

A:

Q: X2-13x>48

A:

Q: 2a+3a=c

A:

Q: -8x 23

A: Given: -8x3y-623 We know that amn=am×n                                                        ..1

Q: What’s 3 + 3 =

A: Given expression 3+3

Q: V-3•V-6 -3 V2

A:

Q: 3x 12 = 2- х+4 х+4

A: Given: 3xx+4=2-12x+4

Q: 2x+5+7=

A: First, combine the numerical terms 5 and 7. 2x+5+7=2x+12=2x+2·6

Q: २e १x- 2 e/~3 5ex

A:

Q: X2+x-35=0

A: It is given that, x2+x-35=0 We have to find the value of x.

Q: -3a + 12a

A: -3a+12a=9a

Q: 8a+72-120=24

A: