2. cot 0= sin 0 = cos 0 = tan 8 = csc = sec 0 = 2

Q: 5. (tan2x + cot2x)² dx

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Q: Sinx=1/2 Cos2x=

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Q: 1+cos2x 3. cotx sin 2x

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Q: If tanA = (5/12)  Then find the value of (sinA+cosA) secA

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Q: (1+cosX)(cscX-cot)=

A: See attached file for a step by step explanation.

Q: 19. sine = and tan 0 =

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Q: Differentiate  (sin(x+a)/cosx)

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Q: Find csc if cot = -16/63 and sin>0

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Q: 1.secB-cosB = tanB sin B 2.cotAcosA + sin A= cscA

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Q: IF 3 TANQ = 3SINQ FIND THE VALUE OF SIN²Q - COS²Q.

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Q: 5 [cot 0 · sec 0 · sin 0]

A: Given: 5cotθ·secθ·sinθ

Q: 7. Verify the following: (sec0 + csc®)(cos0 – sin0) = cot0 – tan0

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Q: cot (0) csc (0) sec2 (0)

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Q: Find sec2x if sin x = 6/10 and sec x < 0

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Q: Solve cos ( tanx) = sin cot! 3 4

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Q: CSCX 1+ cot² x = sinx

A: Given; 1+cot2x = cscx/sinx.

Q: Sin(28) = cos(a) %3D mLa?

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Q: cosx+1=sinx

A: