2. Consider this "Dr. Yan's imaginary" molecule below in line-angle formula. Note that you MAY NOT add or remove lone pairs. : 0=c=N: a) How many CH groups are there in the molecule? b) The formal charge of O is: and the formal charge of N is: c) The overall charge of the molecule:
Basics in Organic Reactions Mechanisms
In organic chemistry, the mechanism of an organic reaction is defined as a complete step-by-step explanation of how a reaction of organic compounds happens. A completely detailed mechanism would relate the first structure of the reactants with the last structure of the products and would represent changes in structure and energy all through the reaction step.
Heterolytic Bond Breaking
Heterolytic bond breaking is also known as heterolysis or heterolytic fission or ionic fission. It is defined as breaking of a covalent bond between two different atoms in which one atom gains both of the shared pair of electrons. The atom that gains both electrons is more electronegative than the other atom in covalent bond. The energy needed for heterolytic fission is called as heterolytic bond dissociation energy.
Polar Aprotic Solvent
Solvents that are chemically polar in nature and are not capable of hydrogen bonding (implying that a hydrogen atom directly linked with an electronegative atom is not found) are referred to as polar aprotic solvents. Some commonly used polar aprotic solvents are acetone, DMF, acetonitrile, DMSO, etc.
Oxygen Nucleophiles
Oxygen being an electron rich species with a lone pair electron, can act as a good nucleophile. Typically, oxygen nucleophiles can be found in these compounds- water, hydroxides and alcohols.
Carbon Nucleophiles
We are aware that carbon belongs to group IV and hence does not possess any lone pair of electrons. Implying that neutral carbon is not a nucleophile then how is carbon going to be nucleophilic? The answer to this is that when a carbon atom is attached to a metal (can be seen in the case of organometallic compounds), the metal atom develops a partial positive charge and carbon develops a partial negative charge, hence making carbon nucleophilic.
Consider this “Dr. Yan’s imaginary” molecule below in line-angle formula. Note that you MAY NOT add or remove lone pairs.
How many CH groups are there in the molecule? ____________
- b) The formal charge of O is:__________; and the formal charge of N is: ____________________
- c) The overall charge of the molecule: ___________
![**Dr. Yan's Imaginary Molecule Exercise**
**2. Consider this “Dr. Yan’s imaginary” molecule below in line-angle formula. Note that you MAY NOT add or remove lone pairs.**
*The diagram displays a molecule structure consisting of a benzene ring with an attachment. The benzene ring is connected via a single line to a sulfur atom (S), which has two lone pairs depicted as two dots (:) on opposite sides of the element symbol. The sulfur atom is further bonded to an oxygen atom (O) with a double bond, also displaying two lone pairs (:) on opposite sides. The oxygen is connected through a single bond to a carbon atom triple-bonded to a nitrogen atom (N), which has one lone pair (:).*
a) **How many CH groups are there in the molecule?** ___________
b) **The formal charge of O is:** ___________; **and the formal charge of N is:** ___________
c) **The overall charge of the molecule:** ___________
**Explanation of the Diagram:**
The diagram provided shows a structural representation of the molecule. In this structure:
- A benzene ring structure (hexagon with alternating double bonds) is depicted.
- The benzene ring is bonded to a sulfur atom that has two lone pairs.
- The sulfur atom is connected to an oxygen atom via a double bond, which has two lone pairs.
- Opposite the sulfur, the oxygen is connected to a carbon atom.
- This carbon is triple-bonded to a nitrogen atom (with one lone pair).
Learners are tasked with identifying the quantities of specific groups and charges based on this structure.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7f9c6ce-7c61-4a7b-90a0-6a641d198bf8%2Faaf94a1d-df32-4016-a7f7-763e9d4a90aa%2Ff2zsf7k_processed.png&w=3840&q=75)
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