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2. Consider the following processes along with their burst time in milliseconds(ms). • Draw the Gantt chart • Calculate Waiting Time of each process • Calculate Average waiting time • Calculate Average Turn Around Time using SJF Non Preemptive Scheduling Algorithm? Process id Burst time (ms) P1 2 P2 3 P3 1 P4 6. P5 3 P6 4

2. Consider the following processes along with their burst time in milliseconds(ms). • Draw the Gantt chart • Calculate Waiting Time of each process • Calculate Average waiting time • Calculate Average Turn Around Time using SJF Non Preemptive Scheduling Algorithm? Process id Burst time (ms) P1 2 P2 3 P3 1 P4 6. P5 3 P6 4

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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2. Consider the following processes along with their burst time in milliseconds(ms). • Draw the Gantt chart • Calculate Waiting Time of each process • Calculate Average waiting time • Calculate Average Turn Around Time using SJF Non Preemptive Scheduling Algorithm? Process id Burst time (ms) P1 2 P2 3 P3 1 P4 6 P5 3 P6 4
Transcribed Image Text:2. Consider the following processes along with their burst time in milliseconds(ms). • Draw the Gantt chart • Calculate Waiting Time of each process • Calculate Average waiting time • Calculate Average Turn Around Time using SJF Non Preemptive Scheduling Algorithm? Process id Burst time (ms) P1 2 P2 3 P3 1 P4 6 P5 3 P6 4
Answol 8 10 12 14 16 18 f9 24 22 waiting Time: Pi= 14 -4 =10 P2= 4-2- 2 P3= 20 - 5-15 P4=22-6=16 P5=19 -3 = 16 P6=10-2=8 Average waiting Time - lot 2+15+ 16+ 16-+8= To tala 67/6=11.16 Turn Around Times Pi=4+10=14 PzE2+2- 4 2- 5+15 = 2u P4= 6+16=22. Ps= 3+ 16=1a Po- 248= 1 o Average Turn Around Time= = 14+4+20 +22+19+10/6 = 14.83.
Transcribed Image Text:Answol 8 10 12 14 16 18 f9 24 22 waiting Time: Pi= 14 -4 =10 P2= 4-2- 2 P3= 20 - 5-15 P4=22-6=16 P5=19 -3 = 16 P6=10-2=8 Average waiting Time - lot 2+15+ 16+ 16-+8= To tala 67/6=11.16 Turn Around Times Pi=4+10=14 PzE2+2- 4 2- 5+15 = 2u P4= 6+16=22. Ps= 3+ 16=1a Po- 248= 1 o Average Turn Around Time= = 14+4+20 +22+19+10/6 = 14.83.
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