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2. Consider the following nonlinear equation e = 7x. (a) The above equation can be reformulated in the form of By taking xo = 0, show that the given form is appropriate to be used in fixed point iteration method. (b) Thus, use the fixed point iteration formula x;+1 = g(x;) to find the root of given nonlinear equation with xo = 0. Stop the iteration when |x;+1 – x;| < 0.000001. Use 6 decimal places in this calculation.

2. Consider the following nonlinear equation e = 7x. (a) The above equation can be reformulated in the form of By taking xo = 0, show that the given form is appropriate to be used in fixed point iteration method. (b) Thus, use the fixed point iteration formula x;+1 = g(x;) to find the root of given nonlinear equation with xo = 0. Stop the iteration when |x;+1 – x;| < 0.000001. Use 6 decimal places in this calculation.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Numerical method

Do your calculation in 4 decimal places unless specified in the question. 2. Consider the following nonlinear equation et = 7x. (a) The above equation can be reformulated in the form of = x By taking xo = 0, show that the given form is appropriate to be used in fixed point iteration method. g(x;) to find the root of 0. Stop the iteration when |x;+1 – x;| < (b) Thus, use the fixed point iteration formula xi+1 given nonlinear equation with xo 0.000001. Use 6 decimal places in this calculation.
Transcribed Image Text:Do your calculation in 4 decimal places unless specified in the question. 2. Consider the following nonlinear equation et = 7x. (a) The above equation can be reformulated in the form of = x By taking xo = 0, show that the given form is appropriate to be used in fixed point iteration method. g(x;) to find the root of 0. Stop the iteration when |x;+1 – x;| < (b) Thus, use the fixed point iteration formula xi+1 given nonlinear equation with xo 0.000001. Use 6 decimal places in this calculation.
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