2. Consider the converse statement "If Pis a point such that PA = PB, then Pis on the perpendicular bisector of segment AB." a. Provide a counterexample in taxicab geometry. (Note: In taxicab geometry, PA = PB means dr(P, A) = dr(P,B).) Illustrate your counterexample on grid paper and explain how it is a counterexample.
2. Consider the converse statement "If Pis a point such that PA = PB, then Pis on the perpendicular bisector of segment AB." a. Provide a counterexample in taxicab geometry. (Note: In taxicab geometry, PA = PB means dr(P, A) = dr(P,B).) Illustrate your counterexample on grid paper and explain how it is a counterexample.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:2. Consider the converse statement "If \( P \) is a point such that \( PA = PB \), then \( P \) is on the perpendicular bisector of segment \( \overline{AB} \)."
a. Provide a counterexample in taxicab geometry. (Note: In taxicab geometry, \( PA = PB \) means \( d_T(P, A) = d_T(P, B) \).) Illustrate your counterexample on grid paper and explain how it is a counterexample.

Transcribed Image Text:A point \( P \) lies on the perpendicular bisector of \( \overline{AB} \) if and only if \( PA = PB \).
Analyze what goes wrong with this theorem in taxicab geometry by completing the following two problems:
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