This is part of a review I'm studying, NOT a graded assignment, please do not reject. Thank you for your help! 2. Concepts of RMS value and complex power under harmonic conditions: In the circuit below, thevoltage has harmonics. The load is a passive element Z(s) = R + Ls, where R = 0.1 Ohm, and L = 1 mH.→2(+)~ √(t)Figure 2: Problem 2: A circuit with harmonics.v(t) = 10 cos(wt) + 2 cos s (2wt + 7) + cos (3wt − 7) v.(1)What is the current's time-domain expression i(t)?• What are the RMS values of the voltage and the current?• What are the real power, reactive power, apparent power, and power factor by the load?Hint: If you use phasor/impedance analysis, please make sure you are studying one harmonic frequency at atime.

Answered: 2. Concepts of RMS value and complex…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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This is part of a review I'm studying, NOT a graded assignment, please do not reject. Thank you for your help!

2. Concepts of RMS value and complex power under harmonic conditions: In the circuit below, the
voltage has harmonics. The load is a passive element Z(s) = R + Ls, where R = 0.1 Ohm, and L = 1 mH.
→2(+)
~ √(t)
Figure 2: Problem 2: A circuit with harmonics.
v(t) = 10 cos(wt) + 2 cos s (2wt + 7) + cos (3wt − 7) v.
(1)
What is the current's time-domain expression i(t)?
• What are the RMS values of the voltage and the current?
• What are the real power, reactive power, apparent power, and power factor by the load?
Hint: If you use phasor/impedance analysis, please make sure you are studying one harmonic frequency at a
time.

Expert Solution

Step 1: Determine the given variables:-

The given circuit diagram is shown below,

$Here comma Voltage comma space straight v open parentheses straight t close parentheses equals 10 space cos open parentheses straight omega straight t close parentheses plus 2 space cos open parentheses 2 straight omega straight t plus straight pi over 6 close parentheses plus cos open parentheses 3 straight omega straight t minus straight pi over 4 close parentheses space straight V. and comma Load comma space straight Z open parentheses straight s close parentheses equals straight R plus sL comma straight R equals 0.1 space straight capital omega. straight L equals 1 space mH.$

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