2. Commercial cherry trees produce fruit according to a normal distribution with an average of 80 kg of cherries per tree and a standard deviation of 13 kg per tree. https://onlinestatbook.com/2/calculators/normal dist.html a. Label the horizontal axis appropriately on the Normal curve at right. b. What is the probability that a tree produces at least 86 kg of cherries? Shade the appropriate area in the figure, and then determine the proportion. c. What is the probability that a tree yields between 75 and 96 kg of cherries?
2. Commercial cherry trees produce fruit according to a normal distribution with an average of 80 kg of cherries per tree and a standard deviation of 13 kg per tree. https://onlinestatbook.com/2/calculators/normal dist.html a. Label the horizontal axis appropriately on the Normal curve at right. b. What is the probability that a tree produces at least 86 kg of cherries? Shade the appropriate area in the figure, and then determine the proportion. c. What is the probability that a tree yields between 75 and 96 kg of cherries?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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**Tasks:**
a. **Labeling the Horizontal Axis:**
- Label the horizontal axis appropriately on the normal curve presented. The axis should help in identifying the yield in kilograms of cherries, centered around the mean, 80 kg.
b. **Probability of Yielding at Least 86 kg:**
- Determine the probability that a tree produces at least 86 kg of cherries. This involves shading the area to the right of 86 kg on the normal distribution curve and calculating the proportion of this area relative to the entire curve.
c. **Probability of Yields Between 75 and 96 kg:**
- Calculate the probability that a tree yields between 75 kg and 96 kg of cherries. Shade the area under the curve between these two values and determine the corresponding proportion.
**Graph Explanation:**
The graph shows a normal distribution curve depicting the cherry yield per tree. The mean, located at the center, is 80 kg. The spread of the curve is determined by the standard deviation, which is 13 kg. The horizontal axis represents the yield in kilograms, while the vertical axis represents the probability density.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F43403b10-66cc-48cc-8f42-f70e2b32561d%2Fa668dd47-4681-489e-bb7b-2bc1701bd2b5%2Ffw5ih6l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Normal Distribution of Cherry Tree Yields**
Commercial cherry trees produce fruit according to a normal distribution with an average of 80 kg of cherries per tree and a standard deviation of 13 kg per tree. For more details on normal distribution calculations, visit [Online Statistics Book](https://onlinestatbook.com/2/calculators/normal_dist.html).
**Tasks:**
a. **Labeling the Horizontal Axis:**
- Label the horizontal axis appropriately on the normal curve presented. The axis should help in identifying the yield in kilograms of cherries, centered around the mean, 80 kg.
b. **Probability of Yielding at Least 86 kg:**
- Determine the probability that a tree produces at least 86 kg of cherries. This involves shading the area to the right of 86 kg on the normal distribution curve and calculating the proportion of this area relative to the entire curve.
c. **Probability of Yields Between 75 and 96 kg:**
- Calculate the probability that a tree yields between 75 kg and 96 kg of cherries. Shade the area under the curve between these two values and determine the corresponding proportion.
**Graph Explanation:**
The graph shows a normal distribution curve depicting the cherry yield per tree. The mean, located at the center, is 80 kg. The spread of the curve is determined by the standard deviation, which is 13 kg. The horizontal axis represents the yield in kilograms, while the vertical axis represents the probability density.
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