2. Calculate the total flux OE through the box shown above if a single charge Q1μC was to be placed at each of the following points:•(x,y,z) = (1,1,1)•(x,y,z) = (1,2,2)(x,y,z) = (3,1,1).(x,y,z) = (2,1,2)(x,y,z) = (2,0,0)(x,y,z) = (2,1,0)February 23, 2024 D!3m2mEF3m

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Answered: 2. Calculate the total flux OE through…

College Physics

11th Edition

ISBN:9781305952300

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Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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1. Let us illustrate the use of the vector form of Coulomb's law by locating a charge of Q1 = 50 nC at A(4, –2,7) and a charge of Q2 = 40 nC at N(6,15,8) in a vacuum. We desire the force exerted on Q, by Q1. 2. A charge QA =-60µC is located at A(6, –4, –7), and a charge Qg = 60µC is at B(4,4,4) in free space. If the distances are given in meters, find: (a) RAB (b) RAB. Determine the vector force exerted on Qa by Qg if €, =: (c)· 10- F/m; (d) 8.854 x 10-12 F/m. 367
4. Two point charges of -30nC and 10nC are located at (3,-2,4) and (0,1,5) above the conducting ground plane z=3. a) Draw the charge equivalent diagram for this problem, b) Find E at (3,4,7) and c) E at (3,8,2)
1. Consider the four point charges shown in the figure on the right, arranged on the edges of a square of side a. a) Find the value of Q (in terms of g), such that the electric field at the center of the square points down (i.e., it only has a -y component). Show all work and justify any assumptions you -29 a a/2 make. b) Assuming Q has the value found in part (a), find the force exerted by the four corner charges on a fifth charge -q placed at the center of the square. c) Also using the result from (a), find the electric field at point P (shown in the figure) created by the four corner charges (there is no charge at the center of the square for this part).
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2. Calculate the total flux OE through the box shown above if a single charge Q 1μC was to be placed at each of the following points: • (x,y,z) = (1,1,1) • (x,y,z) = (1,2,2) (x,y,z) = (3,1,1) . (x,y,z) = (2,1,2) (x,y,z) = (2,0,0) (x,y,z) = (2,1,0) February 23, 2024 D! 3m 2m E F 3m