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2. Calculate the constituents below in units of mass per volume. Give your answers in the most appropriate units (for example, g/L, mg/L, or µg/L depending upon the magnitude of your answer). See Table A-9 in the appendix of your book for necessary information. a. 2 x 10'M PbS (as long as it stays solid, can keep lead out of water) b. 0.830 M CaCO; (important in the carbonate system and ocean acidification) c. 0.070 N Mg(OH)2 (formed during softening in water treatment)

2. Calculate the constituents below in units of mass per volume. Give your answers in the most appropriate units (for example, g/L, mg/L, or µg/L depending upon the magnitude of your answer). See Table A-9 in the appendix of your book for necessary information. a. 2 x 10'M PbS (as long as it stays solid, can keep lead out of water) b. 0.830 M CaCO; (important in the carbonate system and ocean acidification) c. 0.070 N Mg(OH)2 (formed during softening in water treatment)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2. Calculate the constituents below in units of mass per volume. Give your answers in the most appropriate units (for example, g/L, mg/L, or µg/L depending upon the magnitude of your answer). See Table A-9 in the appendix of your book for necessary information. a. 2 x 10' M PbS (as long as it stays solid, can keep lead out of water) b. 0.830 M CACO; (important in the carbonate system and ocean acidification) c. 0.070 N Mg(OH)2 (formed during softening in water treatment) d. 1.50 N HCI (used for neutralizing solutions with high pH)
Transcribed Image Text:2. Calculate the constituents below in units of mass per volume. Give your answers in the most appropriate units (for example, g/L, mg/L, or µg/L depending upon the magnitude of your answer). See Table A-9 in the appendix of your book for necessary information. a. 2 x 10' M PbS (as long as it stays solid, can keep lead out of water) b. 0.830 M CACO; (important in the carbonate system and ocean acidification) c. 0.070 N Mg(OH)2 (formed during softening in water treatment) d. 1.50 N HCI (used for neutralizing solutions with high pH)
TABLE A-9 Typical solubility product constants Equilibrium equation Kyp at 25°C AgCl = Ag* + Cl¯ Al(OH)3 = Al³* + 30H¯ AIPO4 2 Al³+ + PO- BaSO4 2 Ba?+ + so? Cd(OH), = Cd²+ + 20H¯ CdS = Cd²+ + s²- -10 1.76 × 10¬ –33 1.26 X 10 9.84 × 10 1.05 × 10 -21 -10 5.33 X 10-15 -29 1.40 × 10 CdCO3 = Ca²+ + CO? CaCO3 = Ca²+ + CO?- CaF2 = Ca²+ + 2F Ca(OH)2 = Ca²+ + 20H¯ 6.20 × 10-12 4.95 × 10-9 3.45 X 10¬11 7.88 × 10-6 2.02 X 10 Ca3(PO4)2 = 3Ca²+ + 2PO- CASO4 = Ca²+ + SO? Cr(OH); = Cr** + 30H¯ Cu(OH)2 = Cu²+ + 20H¯ CuS = Cu?+ + s²- -33 4.93 × 10-5 6.0 X 10-31 -19 2.0 X 10 1.0 × 10-36 Fe(OH)3 = Fe* + 30H¯ – 39 2.67 X 10 1.3 X 10 FEPO4 2 Fe* + PO FECO, = Fe2+ + CO?- Fe(OH) = Fe²+ + 20H¯ Fes = Fe?+ + S²- -22 3.13 × 10¬11 -17 4.79 X 10 1.57 × 10-19 1.48 X 10 P6CO3 = Pb²+ + CO?- Pb(OH)2 = Pb²+ + 20H¯ PbS = Pb2+ + s²- Mg(OH), = Mg²+ + 20H¯ MGCO3 = Mg* + CO? MNCO3 = Mn²+ + CO}- Mn(OH)2 2 Mn²* + 20H Ni²+ + CO Ni(OH)2 = Ni²+ + 20H¯ Nis = Ni?+ + S²- SrCO3 2 Sr* + CO Zn(OH), = Zn²+ + 20H + s?- -13 -20 1.40 X 10 8.81 × 10' 5.66 X 10 1.15 × 10 -29 -12 -5 11 2.23 × 10¬ -13 2.04 X 10 1.45 × 10¬7 NİCO3 5.54 X 10¬16 1.08 X 10 -21 -10 5.60 X 10 7.68 × 10' 2.91 × 10 -17 ZnS 2 Zn 2+ -25 (Sources: Linde, 2000; Sawyer, McCarty, and Parkin, 2003; Weast, 1983.)
Transcribed Image Text:TABLE A-9 Typical solubility product constants Equilibrium equation Kyp at 25°C AgCl = Ag* + Cl¯ Al(OH)3 = Al³* + 30H¯ AIPO4 2 Al³+ + PO- BaSO4 2 Ba?+ + so? Cd(OH), = Cd²+ + 20H¯ CdS = Cd²+ + s²- -10 1.76 × 10¬ –33 1.26 X 10 9.84 × 10 1.05 × 10 -21 -10 5.33 X 10-15 -29 1.40 × 10 CdCO3 = Ca²+ + CO? CaCO3 = Ca²+ + CO?- CaF2 = Ca²+ + 2F Ca(OH)2 = Ca²+ + 20H¯ 6.20 × 10-12 4.95 × 10-9 3.45 X 10¬11 7.88 × 10-6 2.02 X 10 Ca3(PO4)2 = 3Ca²+ + 2PO- CASO4 = Ca²+ + SO? Cr(OH); = Cr** + 30H¯ Cu(OH)2 = Cu²+ + 20H¯ CuS = Cu?+ + s²- -33 4.93 × 10-5 6.0 X 10-31 -19 2.0 X 10 1.0 × 10-36 Fe(OH)3 = Fe* + 30H¯ – 39 2.67 X 10 1.3 X 10 FEPO4 2 Fe* + PO FECO, = Fe2+ + CO?- Fe(OH) = Fe²+ + 20H¯ Fes = Fe?+ + S²- -22 3.13 × 10¬11 -17 4.79 X 10 1.57 × 10-19 1.48 X 10 P6CO3 = Pb²+ + CO?- Pb(OH)2 = Pb²+ + 20H¯ PbS = Pb2+ + s²- Mg(OH), = Mg²+ + 20H¯ MGCO3 = Mg* + CO? MNCO3 = Mn²+ + CO}- Mn(OH)2 2 Mn²* + 20H Ni²+ + CO Ni(OH)2 = Ni²+ + 20H¯ Nis = Ni?+ + S²- SrCO3 2 Sr* + CO Zn(OH), = Zn²+ + 20H + s?- -13 -20 1.40 X 10 8.81 × 10' 5.66 X 10 1.15 × 10 -29 -12 -5 11 2.23 × 10¬ -13 2.04 X 10 1.45 × 10¬7 NİCO3 5.54 X 10¬16 1.08 X 10 -21 -10 5.60 X 10 7.68 × 10' 2.91 × 10 -17 ZnS 2 Zn 2+ -25 (Sources: Linde, 2000; Sawyer, McCarty, and Parkin, 2003; Weast, 1983.)
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