2. Calculate the constituents below in units of mass per volume. Give your answers in the most appropriate units (for example, g/L, mg/L, or µg/L depending upon the magnitude of your answer). See Table A-9 in the appendix of your book for necessary information. a. 2 x 10'M PbS (as long as it stays solid, can keep lead out of water) b. 0.830 M CaCO; (important in the carbonate system and ocean acidification) c. 0.070 N Mg(OH)2 (formed during softening in water treatment)
2. Calculate the constituents below in units of mass per volume. Give your answers in the most appropriate units (for example, g/L, mg/L, or µg/L depending upon the magnitude of your answer). See Table A-9 in the appendix of your book for necessary information. a. 2 x 10'M PbS (as long as it stays solid, can keep lead out of water) b. 0.830 M CaCO; (important in the carbonate system and ocean acidification) c. 0.070 N Mg(OH)2 (formed during softening in water treatment)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![2. Calculate the constituents below in units of mass per volume. Give your answers in the most
appropriate units (for example, g/L, mg/L, or µg/L depending upon the magnitude of your
answer). See Table A-9 in the appendix of your book for necessary information.
a. 2 x 10' M PbS (as long as it stays solid, can keep lead out of water)
b. 0.830 M CACO; (important in the carbonate system and ocean acidification)
c. 0.070 N Mg(OH)2 (formed during softening in water treatment)
d. 1.50 N HCI (used for neutralizing solutions with high pH)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2e5279c-8220-4351-a871-49f077cb4af8%2Fc1b46bef-ec8c-4400-a71c-f559919da782%2Fr84ymsg_processed.png&w=3840&q=75)
Transcribed Image Text:2. Calculate the constituents below in units of mass per volume. Give your answers in the most
appropriate units (for example, g/L, mg/L, or µg/L depending upon the magnitude of your
answer). See Table A-9 in the appendix of your book for necessary information.
a. 2 x 10' M PbS (as long as it stays solid, can keep lead out of water)
b. 0.830 M CACO; (important in the carbonate system and ocean acidification)
c. 0.070 N Mg(OH)2 (formed during softening in water treatment)
d. 1.50 N HCI (used for neutralizing solutions with high pH)
![TABLE A-9
Typical solubility product constants
Equilibrium equation
Kyp at 25°C
AgCl = Ag* + Cl¯
Al(OH)3 = Al³* + 30H¯
AIPO4 2 Al³+ + PO-
BaSO4 2 Ba?+ + so?
Cd(OH), = Cd²+ + 20H¯
CdS = Cd²+ + s²-
-10
1.76 × 10¬
–33
1.26 X 10
9.84 × 10
1.05 × 10
-21
-10
5.33 X 10-15
-29
1.40 × 10
CdCO3 = Ca²+ + CO?
CaCO3 = Ca²+ + CO?-
CaF2 = Ca²+ + 2F
Ca(OH)2 = Ca²+ + 20H¯
6.20 × 10-12
4.95 × 10-9
3.45 X 10¬11
7.88 × 10-6
2.02 X 10
Ca3(PO4)2 = 3Ca²+ + 2PO-
CASO4 = Ca²+ + SO?
Cr(OH); = Cr** + 30H¯
Cu(OH)2 = Cu²+ + 20H¯
CuS = Cu?+ + s²-
-33
4.93 × 10-5
6.0 X 10-31
-19
2.0 X 10
1.0 × 10-36
Fe(OH)3 = Fe* + 30H¯
– 39
2.67 X 10
1.3 X 10
FEPO4 2 Fe* + PO
FECO, = Fe2+ + CO?-
Fe(OH) = Fe²+ + 20H¯
Fes = Fe?+ + S²-
-22
3.13 × 10¬11
-17
4.79 X 10
1.57 × 10-19
1.48 X 10
P6CO3 = Pb²+ + CO?-
Pb(OH)2 = Pb²+ + 20H¯
PbS = Pb2+ + s²-
Mg(OH), = Mg²+ + 20H¯
MGCO3 = Mg* + CO?
MNCO3 = Mn²+ + CO}-
Mn(OH)2 2 Mn²* + 20H
Ni²+ + CO
Ni(OH)2 = Ni²+ + 20H¯
Nis = Ni?+ + S²-
SrCO3 2 Sr* + CO
Zn(OH), = Zn²+ + 20H
+ s?-
-13
-20
1.40 X 10
8.81 × 10'
5.66 X 10
1.15 × 10
-29
-12
-5
11
2.23 × 10¬
-13
2.04 X 10
1.45 × 10¬7
NİCO3
5.54 X 10¬16
1.08 X 10
-21
-10
5.60 X 10
7.68 × 10'
2.91 × 10
-17
ZnS 2 Zn
2+
-25
(Sources: Linde, 2000; Sawyer, McCarty, and Parkin, 2003; Weast, 1983.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2e5279c-8220-4351-a871-49f077cb4af8%2Fc1b46bef-ec8c-4400-a71c-f559919da782%2F9i9nj_processed.png&w=3840&q=75)
Transcribed Image Text:TABLE A-9
Typical solubility product constants
Equilibrium equation
Kyp at 25°C
AgCl = Ag* + Cl¯
Al(OH)3 = Al³* + 30H¯
AIPO4 2 Al³+ + PO-
BaSO4 2 Ba?+ + so?
Cd(OH), = Cd²+ + 20H¯
CdS = Cd²+ + s²-
-10
1.76 × 10¬
–33
1.26 X 10
9.84 × 10
1.05 × 10
-21
-10
5.33 X 10-15
-29
1.40 × 10
CdCO3 = Ca²+ + CO?
CaCO3 = Ca²+ + CO?-
CaF2 = Ca²+ + 2F
Ca(OH)2 = Ca²+ + 20H¯
6.20 × 10-12
4.95 × 10-9
3.45 X 10¬11
7.88 × 10-6
2.02 X 10
Ca3(PO4)2 = 3Ca²+ + 2PO-
CASO4 = Ca²+ + SO?
Cr(OH); = Cr** + 30H¯
Cu(OH)2 = Cu²+ + 20H¯
CuS = Cu?+ + s²-
-33
4.93 × 10-5
6.0 X 10-31
-19
2.0 X 10
1.0 × 10-36
Fe(OH)3 = Fe* + 30H¯
– 39
2.67 X 10
1.3 X 10
FEPO4 2 Fe* + PO
FECO, = Fe2+ + CO?-
Fe(OH) = Fe²+ + 20H¯
Fes = Fe?+ + S²-
-22
3.13 × 10¬11
-17
4.79 X 10
1.57 × 10-19
1.48 X 10
P6CO3 = Pb²+ + CO?-
Pb(OH)2 = Pb²+ + 20H¯
PbS = Pb2+ + s²-
Mg(OH), = Mg²+ + 20H¯
MGCO3 = Mg* + CO?
MNCO3 = Mn²+ + CO}-
Mn(OH)2 2 Mn²* + 20H
Ni²+ + CO
Ni(OH)2 = Ni²+ + 20H¯
Nis = Ni?+ + S²-
SrCO3 2 Sr* + CO
Zn(OH), = Zn²+ + 20H
+ s?-
-13
-20
1.40 X 10
8.81 × 10'
5.66 X 10
1.15 × 10
-29
-12
-5
11
2.23 × 10¬
-13
2.04 X 10
1.45 × 10¬7
NİCO3
5.54 X 10¬16
1.08 X 10
-21
-10
5.60 X 10
7.68 × 10'
2.91 × 10
-17
ZnS 2 Zn
2+
-25
(Sources: Linde, 2000; Sawyer, McCarty, and Parkin, 2003; Weast, 1983.)
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