2. By using reduction of order method find another solution y(t) for t²y". 3ty' + 4y = 0, t> 0 given that y₁(t) = t² is a solution. Determine the general solution. Remark: the set {yı(t), y2(t)} is a fundamental set of solutions. -

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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### Problem 2: Reduction of Order Method

By using the **reduction of order method**, find another solution \( y_2(t) \) for the differential equation:

\[ t^2 y'' - 3ty' + 4y = 0, \quad t > 0 \]

Given that \( y_1(t) = t^2 \) is a solution, determine the general solution.

**Remark:** The set \(\{y_1(t), y_2(t)\}\) is a fundamental set of solutions.

#### Solution Outline:

1. **Step 1: Assume a form for the second solution.** Since \( y_1(t) \) is known, assume \( y_2(t) = v(t) y_1(t) \) where \( v(t) \) is a function to be determined.

2. **Step 2: Compute derivatives.** Find \( y_2' \) and \( y_2'' \) with the product rule:
    - \( y_2(t) = v(t)t^2 \)
    - \( y_2' = v'(t)t^2 + 2t v(t) \)
    - \( y_2'' = v''(t)t^2 + 4t v'(t) + 2v(t) \)

3. **Step 3: Substitute into the original differential equation.** Plug these into the original differential equation \( t^2 y'' - 3ty' + 4y = 0 \).

4. **Step 4: Simplify the equation.** This will lead to a derivative equation for \( v(t) \).

5. **Step 5: Solve for \( v(t) \).** This involves integrating to find \( v(t) \).

6. **Step 6: Determine \( y_2(t) \) and the general solution.** Combine the solutions to write the general solution.

#### Example Walkthrough:

1. Assume \( y_2(t) = v(t) t^2 \).
2. Calculate:
    - \( y_2' = v'(t) t^2 + 2t v(t) \)
    - \( y_2'' = v''(t) t^2 + 4t v'(t) + 2 v(t) \)
3. Substitute \( y_2, y_2
Transcribed Image Text:### Problem 2: Reduction of Order Method By using the **reduction of order method**, find another solution \( y_2(t) \) for the differential equation: \[ t^2 y'' - 3ty' + 4y = 0, \quad t > 0 \] Given that \( y_1(t) = t^2 \) is a solution, determine the general solution. **Remark:** The set \(\{y_1(t), y_2(t)\}\) is a fundamental set of solutions. #### Solution Outline: 1. **Step 1: Assume a form for the second solution.** Since \( y_1(t) \) is known, assume \( y_2(t) = v(t) y_1(t) \) where \( v(t) \) is a function to be determined. 2. **Step 2: Compute derivatives.** Find \( y_2' \) and \( y_2'' \) with the product rule: - \( y_2(t) = v(t)t^2 \) - \( y_2' = v'(t)t^2 + 2t v(t) \) - \( y_2'' = v''(t)t^2 + 4t v'(t) + 2v(t) \) 3. **Step 3: Substitute into the original differential equation.** Plug these into the original differential equation \( t^2 y'' - 3ty' + 4y = 0 \). 4. **Step 4: Simplify the equation.** This will lead to a derivative equation for \( v(t) \). 5. **Step 5: Solve for \( v(t) \).** This involves integrating to find \( v(t) \). 6. **Step 6: Determine \( y_2(t) \) and the general solution.** Combine the solutions to write the general solution. #### Example Walkthrough: 1. Assume \( y_2(t) = v(t) t^2 \). 2. Calculate: - \( y_2' = v'(t) t^2 + 2t v(t) \) - \( y_2'' = v''(t) t^2 + 4t v'(t) + 2 v(t) \) 3. Substitute \( y_2, y_2
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