2. Apple's Mac computer batteries last for 7 hours on a single charge with a standard deviation of 20minutes. A new supplier offers them a battery that they say will have increased battery life. A randomsampling of twelve of the new batteries are tested and found to have a sample mean of 7 hours and 22minutes and a sample standard deviation of 34 minutes. Does this new battery match the company's claim(to 95% confidence)? Perform a hypothesis test, showing all steps.

Answered: Image /qna-images/answer/19983e2b-9d88-4a20-9f15-ec80e0c69d43.jpg

Answered: 2. Apple's Mac computer batteries last…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Similar questions

The average age of Americans is 72 years. A group of 25 individuals participated in a new diet program to see if it increased their lifespan. The group was evaluated a few decades later to see if the program made the subjects live longer. The mean age for the new diet group was 79 years with a standard deviation of 6.5. If a t-test was conducted, would this be a one-tailed (directional) or two-tailed (non-directional) hypothesis? Group of answer choices
A researcher tests whether listening to music while taking an exam has any effect. The population mean of people taking an exam while not listening to music is 50, with a standard deviation of 12. The researcher tests a sample of 57 people who listen to music while taking an exam and they produce a mean of 54.36. Using a one-tailed test with a p value of .05, the critical value is -1.65 and 1.65. Make a decision about your hypothesis.
A quiz related to digital knowledge was conducted. The quiz had 10 questions and covered topics such as the purpose of browser cookies, phishing scams, and privacy policies. The survey was given to 50 people. The mean score is 4.1 with a standard deviation of 2.6. We want to know if the data provide evidence that the mean score in the population is lower than 5. We will use alpha = 0.05 to make our decision. What is the null hypothesis for this question? Group of answer choices a. The proportion of people who pass the test is 5. b. The mean test score of the population is 5. c. The mean test score of the 50 people who took the test is 5. d.The standard deviation is 2.6
A college lacrosse coach wants to know if sending his players to a training camp will help them to score more goals. He knows that the population mean scoring per game for all college teams is 12.4 per game, with a standard deviation of 2.48. He takes a sample of 36 teams that have been to this training camp and he finds that they averaged 13.3 goals per game. Will participating in this training camp help his team score more goals? Use alpha .05 to answer this question.
2) A restaurant association claims that the average amount a family spends per year eating out is $2700. Suppose you are a consumer reporter and want to test this claim. You select a random sample of 32 homes and obtain that their mean is $2850 with a standard deviation of $270. using α= 0.05, do you have enough evidence to reject the association's claim?
Two treatments for a new infectious disease have been developed to reduce hospitalizations. Each treatment was given to different groups of patients. Treatment 1 was given to 65 people. Subjects of treatment 1 had a mean hospital stay of 5.6 days with a standard deviation of 2.6 days. Treatment 2 was given to 54 people. Subjects of treatment 2 had a mean hospital stay of 8.4 days with a standard deviation of 3.0 days. Use the method of hypothesis testing to test the claim that the mean time in the hospital for treatment 1 is shorter than the mean time in the hospital for treatment 2 assuming a 0.05 significance level. (a) List the null and alternative hypotheses for this test. (b) Compute the value of the test statistic (c) Determine the rejection region.(d) Determine whether or not we can reject the null hypothesis.
A custodian wishes to compare two competing floor waxes to decide which one is best. He believes that the mean of WaxWin is not equal to the mean of WaxCo. In a random sample of 12 floors of WaxWin and 20 of WaxCo. WaxWin had a mean lifetime of 27.6 with a standard deviation of 8.8 and WaxCo had a mean lifetime of 20.3 with a standard deviation of 7.6. Perform a hypothesis test using a significance level of 0.01 to help him decide. Let WaxWin be sample 1 and WaxCo be sample 2 The correct hypotheses are: HA: P1 > µ2(claim) Ho: µ1 2 µ2 HA: µ1 < µ2(claim) Ho: µ1 = µ2 HA: H1 + H2(claim) Since the level of significance is 0.01 the critical value is 2.836 and -2.836 The test statistic is: (round to 3 places) The p-value is: (round to 3 places)
A custodian wishes to compare two competing floor waxes to decide which one is best. He believes that the mean of WaxWin is less than the mean of WaxCo. In a random sample of 20 floors of WaxWin and 17 of WaxCo. WaxWin had a mean lifetime of 26.4 with a standard deviation of 8.6 and WaxCo had a mean lifetime of 27.2 with a standard deviation of 6.6. Perform a hypothesis test using a significance level of 0.05 to help him decide. Let WaxWin be sample 1 and WaxCo be sample 2 The correct hypotheses are: Ο Ηο: μι < με HA₁₂(claim) Ο Ηρ: με 2 με HA: 1₂(claim) O Ho: ₁ = ₂ HAM12(claim) Since the level of significance is 0.05 the critical value is -1.69 (round to 3 places) The test statistic is: The p-value is: (round to 3 places)

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