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2. Analyze the following sequential circuit by determining the truth table. (Complete Output and Next State columns in the truth table.) X Y Z Full Adder Present State Z(Q(t)) 0 0 0 0 1 1 1 1 X 0 0 1 1 0 0 1 1 Inputs Y 0 1 0 1 0 1 0 1 clock K C Output S S Next State Q(t+1)

2. Analyze the following sequential circuit by determining the truth table. (Complete Output and Next State columns in the truth table.) X Y Z Full Adder Present State Z(Q(t)) 0 0 0 0 1 1 1 1 X 0 0 1 1 0 0 1 1 Inputs Y 0 1 0 1 0 1 0 1 clock K C Output S S Next State Q(t+1)

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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**Title: Analysis of Sequential Circuit Using a Truth Table** ### Problem Statement: Analyze the following sequential circuit by determining the truth table. (Complete the Output and Next State columns in the truth table.) ### Circuit Diagram: The diagram features a sequential circuit that includes: 1. **Full Adder**: - Inputs: X, Y, Z - Outputs: Sum (S) and Carry (C) 2. **JK Flip-Flop**: - Inputs: J, K, Clock (C) - Outputs: Q (Next state) - Receives the carry (C) from the Full Adder ### Truth Table: The table below is to be completed using the given inputs and determining the outputs and next states. | Present State (Z(Q(t))) | Inputs | Output | Next State | |-------------------------|--------|--------|------------| | | X Y | S | Q(t+1) | | 0 | 0 0 | | | | 0 | 0 1 | | | | 0 | 1 0 | | | | 0 | 1 1 | | | | 1 | 0 0 | | | | 1 | 0 1 | | | | 1 | 1 0 | | | | 1 | 1 1 | | | ### Explanation: - **Present State (Z(Q(t)))**: The current state of the JK flip-flop. - **Inputs (X, Y)**: The inputs provided to the Full Adder. - **Output (S)**: The sum output from the Full Adder. - **Next State (Q(t+1))**: The state of the JK flip-flop at the next time step, determined by the current inputs and present state. ### Instructions: 1. Fill in the truth table by analyzing the circuit logic: - Determine the output (S) for each combination of inputs (X, Y) using the Full Adder. - Calculate the next state (Q(t+1)) using the JK flip-flop logic with the given clock and carry input (C). This exercise helps
Transcribed Image Text:**Title: Analysis of Sequential Circuit Using a Truth Table** ### Problem Statement: Analyze the following sequential circuit by determining the truth table. (Complete the Output and Next State columns in the truth table.) ### Circuit Diagram: The diagram features a sequential circuit that includes: 1. **Full Adder**: - Inputs: X, Y, Z - Outputs: Sum (S) and Carry (C) 2. **JK Flip-Flop**: - Inputs: J, K, Clock (C) - Outputs: Q (Next state) - Receives the carry (C) from the Full Adder ### Truth Table: The table below is to be completed using the given inputs and determining the outputs and next states. | Present State (Z(Q(t))) | Inputs | Output | Next State | |-------------------------|--------|--------|------------| | | X Y | S | Q(t+1) | | 0 | 0 0 | | | | 0 | 0 1 | | | | 0 | 1 0 | | | | 0 | 1 1 | | | | 1 | 0 0 | | | | 1 | 0 1 | | | | 1 | 1 0 | | | | 1 | 1 1 | | | ### Explanation: - **Present State (Z(Q(t)))**: The current state of the JK flip-flop. - **Inputs (X, Y)**: The inputs provided to the Full Adder. - **Output (S)**: The sum output from the Full Adder. - **Next State (Q(t+1))**: The state of the JK flip-flop at the next time step, determined by the current inputs and present state. ### Instructions: 1. Fill in the truth table by analyzing the circuit logic: - Determine the output (S) for each combination of inputs (X, Y) using the Full Adder. - Calculate the next state (Q(t+1)) using the JK flip-flop logic with the given clock and carry input (C). This exercise helps
**J-K Flip-Flop Characteristic Table** Below is the characteristic table for the J-K flip-flop, which is used in digital circuits to store one bit of data. The table helps in understanding the behavior of the J-K flip-flop for different combinations of inputs. | J | K | Q(t+1) | |---|---|--------| | 0 | 0 | Q(t) | | 0 | 1 | 0 | | 1 | 0 | 1 | | 1 | 1 | Q’(t) | **Explanation:** - **Row 1:** When both J and K are 0, the next state Q(t+1) remains the same as the current state Q(t), indicating no change. - **Row 2:** When J is 0 and K is 1, the next state Q(t+1) is 0, resetting the flip-flop. - **Row 3:** When J is 1 and K is 0, the next state Q(t+1) is 1, setting the flip-flop. - **Row 4:** When both J and K are 1, the next state Q(t+1) is the complement of the current state, toggling the flip-flop. This functionality allows the J-K flip-flop to serve as a memory storage element in various digital systems.
Transcribed Image Text:**J-K Flip-Flop Characteristic Table** Below is the characteristic table for the J-K flip-flop, which is used in digital circuits to store one bit of data. The table helps in understanding the behavior of the J-K flip-flop for different combinations of inputs. | J | K | Q(t+1) | |---|---|--------| | 0 | 0 | Q(t) | | 0 | 1 | 0 | | 1 | 0 | 1 | | 1 | 1 | Q’(t) | **Explanation:** - **Row 1:** When both J and K are 0, the next state Q(t+1) remains the same as the current state Q(t), indicating no change. - **Row 2:** When J is 0 and K is 1, the next state Q(t+1) is 0, resetting the flip-flop. - **Row 3:** When J is 1 and K is 0, the next state Q(t+1) is 1, setting the flip-flop. - **Row 4:** When both J and K are 1, the next state Q(t+1) is the complement of the current state, toggling the flip-flop. This functionality allows the J-K flip-flop to serve as a memory storage element in various digital systems.
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flip flop:-

A flip-flop is a type of electronic circuit that has two stable states and can be used to store data. The two states are usually represented by the numbers 0 and 1. Flip-flops are the basic building blocks of digital circuits.

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