2. An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining. A sample of 240 brakes using Compound 1 yields an average brake life of 42,783 miles. A sample of 230 brakes using Compound 2 yields an average brake life of 40,727 miles. Assume that the population standard deviation for Compound 1 is 1639 miles, while the population standard deviation for Compound 2 is 4130 miles. Determine the 80% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2. n, 240 X= 42,783 e : 1639 nz= 230 X2= 40,727 2: 4130 C 80 Step 1. Find the critical value that should be used in constructing the confidence interval. Answer: 42,783-40,727 I6394130

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Step 2. Construct the 80% confidence interval. Round your answers to the nearest
whole number.
Answer: Lower endpoint:
Upper endpoint:
Transcribed Image Text:Step 2. Construct the 80% confidence interval. Round your answers to the nearest whole number. Answer: Lower endpoint: Upper endpoint:
Step 1. Find the critical value that should be used in constructing the confidence
interval.
n=181
n2 = 197
*=88.9 Q z 15.73
Answer: 2.326
88.1-63.9-2.324
X, 63.9
2= 17, 35
88.1-63.7 t2.326
2.2.33
C0.98
Step 2. Construct the 98% confidence interval. Round your answers to one decimal
place.
Answer: Lower endpoint: 21.042
Upper endpoint: 28.958
2.
An investigator compares the durability of two different compounds used in the
manufacture of a certain automobile brake lining. A sample of 240 brakes using
Compound 1 yields an average brake life of 42,783 miles. A sample of 230 brakes using
Compound 2 yields an average brake life of 40,727 miles. Assume that the population
standard deviation for Compound 1 is 1639 miles, while the population standard
deviation for Compound 2 is 4130 miles. Determine the 80% confidence interval for
the true difference between average lifetimes for brakes using Compound 1 and brakes
using Compound 2.
6, - 1639
0,:4130
n, 240
X= 42,783
230
'ד1 ר ,0ד- ךא
C 80
Step 1. Find the critical value that should be used in constructing the confidence
interval.
Answer:
42,783-40,727
240
236
MAT 106.04 Professor Felix
89 of
Transcribed Image Text:Step 1. Find the critical value that should be used in constructing the confidence interval. n=181 n2 = 197 *=88.9 Q z 15.73 Answer: 2.326 88.1-63.9-2.324 X, 63.9 2= 17, 35 88.1-63.7 t2.326 2.2.33 C0.98 Step 2. Construct the 98% confidence interval. Round your answers to one decimal place. Answer: Lower endpoint: 21.042 Upper endpoint: 28.958 2. An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining. A sample of 240 brakes using Compound 1 yields an average brake life of 42,783 miles. A sample of 230 brakes using Compound 2 yields an average brake life of 40,727 miles. Assume that the population standard deviation for Compound 1 is 1639 miles, while the population standard deviation for Compound 2 is 4130 miles. Determine the 80% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2. 6, - 1639 0,:4130 n, 240 X= 42,783 230 'ד1 ר ,0ד- ךא C 80 Step 1. Find the critical value that should be used in constructing the confidence interval. Answer: 42,783-40,727 240 236 MAT 106.04 Professor Felix 89 of
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