2. An 88.5 gram piece of iron initially at 78.8°C is place in a beaker containing 244 grams of water at 18.8°C. When thermal equilibrium is reached, what is the final temperature? The specific heat capacity for iron is 0.449 J/(g.°C). Assume no heat loss to the surroundings. Assume no heat lost to the surroundings: Heat released by the metal = Heat absorbed by water %3D -qmetal = qwater > qmetal + qwater = 0 %3D mmetalCmetalATmetal + mwaterCwaterATwater = TF = 21.0 °C

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2. An 88.5 gram piece of iron initially at 78.8°C is place in a beaker containing 244 grams of
water at 18.8°C. When thermal equilibrium is reached, what is the final temperature? The
specific heat capacity for iron is 0.449 J/(g·°C). Assume no heat loss to the surroundings.
Assume no heat lost to the surroundings: Heat released by the metal = Heat absorbed by water
%3D
→ qmetal + qwater = 0
%3|
-qmetal = qwater
%3D
mmetalCmetalATmetal + mwaterCwaterATwater = 0
TF = 21.0 °C
%3D
Transcribed Image Text:2. An 88.5 gram piece of iron initially at 78.8°C is place in a beaker containing 244 grams of water at 18.8°C. When thermal equilibrium is reached, what is the final temperature? The specific heat capacity for iron is 0.449 J/(g·°C). Assume no heat loss to the surroundings. Assume no heat lost to the surroundings: Heat released by the metal = Heat absorbed by water %3D → qmetal + qwater = 0 %3| -qmetal = qwater %3D mmetalCmetalATmetal + mwaterCwaterATwater = 0 TF = 21.0 °C %3D
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