2. An 8-m long steel column is pinned at the top and fixed at the bottom. The column is provided withlateral support 3m from the top in the weak direction.The properties of the column section are as follows:Ix = 178x10 mm*ly = 18.8x10 mmA = 8129mm¹Fy = 400 MpaK = effective length factorK = 1.0 when both ends are pinnedK = 0.5 when both ends are fixedK = 0.7 when one end is fixed and the other end is pinneda.What is the critical effective slenderness ratio?b.What is the buckling stress of the column?c. Calculate the critical load P in KN.

- Critical Effective slenderness ratio about x axis ; λ = KLxrx K = 0.7 Since one end is fixed and…

2. An 8-m long steel column is pinned at the top and fixed at the bottom. The column is provided with lateral support 3m from the top in the weak direction. The properties of the column section are as follows: Ix = 178x10 mm ly=18.8x10 mm A = 8129mm² Fy = 400 Mpa K = effective length factor K = 1.0 when both ends are pinned K = 0.5 when both ends are fixed K = 0.7 when one end is fixed and the other end is pinned a. What is the critical effective slenderness ratio? b. What is the buckling stress of the column? c. Calculate the critical load P in KN.

2. An 8-m long steel column is pinned at the top and fixed at the bottom. The column is provided with lateral support 3m from the top in the weak direction. The properties of the column section are as follows: Ix = 178x10 mm ly=18.8x10 mm A = 8129mm² Fy = 400 Mpa K = effective length factor K = 1.0 when both ends are pinned K = 0.5 when both ends are fixed K = 0.7 when one end is fixed and the other end is pinned a. What is the critical effective slenderness ratio? b. What is the buckling stress of the column? c. Calculate the critical load P in KN.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The truss shown in figure below is made up of bars 2 mlong. Find the load carried by the members AB, GE, and CD.
Design the shear reinforcement for the beam shown in figure below assuming it resists an ultimate shear force at distance d from the face of the support of 450 kN. The characteristic material strengths are fok= 25 N/mm²and fm = 500 N/mm² 450 kN d= 500 mm -4H25 b= 300 mm
For the exact in the figure tensile strength = 8000 N / cm ^ 2 compression safety = 3000 N / cm ^ 2 calculate the largest Mx moment that the section can carry.
For the section shown, if the distance from the N.A to the steel centroid is 350 mm, 1944.4 x 10^6 mm^4, Es = 200 GPa, Ec = 20 GPa and M = -50 kN.m, then the strain in steel is b P -185.3 MPa O -926 x 10^-6 O 926 x 10^-6 O 185.3 MPa O zero O
Need asap
Determine (approximately) the forces in the members of the truss shown below. Show your solution including units and the free body diagrams. 20 KN F 3 m A 10 kN 4 m E 20 KN 4 m D C 10 KN
The steel truss (E =200 GPa) shown in figure below has a cross-sectional area of 1920 mm². Determine: a. The largest allowable load F if the change in length of member BD is not to exceed 1.6 mm and a factor of safety of 2.5. b. The displacement of support D due to the load calculated in part a. 5m 6m A C F
Use 3 decimal places
A simply supported girder spans 10 m. It carries two beams each at 3.5 m from the supports. The concentrated load from each beam is 70 kN
A steel column carries an axial load of 808 kN and a moment of 76 kN-m at the top and moment at the bottom which is only70% of the moment at the top. The two moments are in opposite direction and applied about the x-axis and the steel section has the following properties: A = 13080 mm2 rx = 109 mm ry = 94 mm Sx = 1200 x 103 mm3 K = 1.0 L= 3.6 m E = 200,000 Mpa Fy = 248 Mpa Use NSCP specification for compressive stress and Fb =148 Mpa. Determine the Allowable Compressive Stress.
For the truss shown in Figure 2.3b, determine the force in member KP if x = 5 m, y = 7 m and P = 7.94 kN. Indicate whether the member is in tension or compression. (Note: Use negative sign (-) if the member is in compression.) 7 panels at x m = 7x m В J D K L y F A х М N H G P P kN P kN