2. a. A particle is undergoing a uniform rectilinear motion and the displacement as a function of time is given by r(t) = 6tª- 2t³ -12t²+3t+3 where r is in meters and t is in seconds. b. What is a uniform rectilinear motion? c. Find the average acceleration of the particle between t = 0 and t=2s d. When is the acceleration zero?

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**Physics - Motion of Particles**

**2.**
   **a.** A particle is undergoing a uniform rectilinear motion and the displacement as a function of time is given by: 
   \[
   \mathbf{r}(t) = 6t^4 - 2t^3 - 12t^2 + 3t + 3
   \]
   where \( r \) is in meters and \( t \) is in seconds.
   
   **b.** What is a uniform rectilinear motion?

   **c.** Find the average acceleration of the particle between \( t = 0 \) and \( t = 2s \).

   **d.** When is the acceleration zero?

**3.** The position of a particular particle as a function of time is given by: 
   \[
   \mathbf{r} = (9.60 t \, \mathbf{i} + 8.58 \, \mathbf{j} - 1.00 t^2 \, \mathbf{k}) \text{ meters}
   \]
   Determine the particle’s velocity and acceleration as a function of time.

---

### Detailed Explanation:

**2.**

**(a)** The given function describes the displacement \(\mathbf{r}(t)\) of a particle in uniform rectilinear motion. The displacement is represented by a polynomial equation in terms of time \(t\).

**(b)** Uniform rectilinear motion refers to motion in a straight line with uniform (constant) velocity, meaning that both the direction and speed of the motion remain consistent over time.

**(c)** To find the average acceleration, you need to calculate the change in velocity over the change in time. The first step is to differentiate the displacement function \(\mathbf{r}(t)\) to find the velocity function \( \mathbf{v}(t) \):
   \[
   \mathbf{v}(t) = \frac{d}{dt}[6t^4 - 2t^3 - 12t^2 + 3t + 3]
   \]
   Then, differentiate the velocity function to find the acceleration function \( \mathbf{a}(t) \):
   \[
   \mathbf{a}(t) = \frac{d}{dt} \mathbf{v}(t)
   \]
   Evaluate \( \mathbf{a}(t) \)
Transcribed Image Text:**Physics - Motion of Particles** **2.** **a.** A particle is undergoing a uniform rectilinear motion and the displacement as a function of time is given by: \[ \mathbf{r}(t) = 6t^4 - 2t^3 - 12t^2 + 3t + 3 \] where \( r \) is in meters and \( t \) is in seconds. **b.** What is a uniform rectilinear motion? **c.** Find the average acceleration of the particle between \( t = 0 \) and \( t = 2s \). **d.** When is the acceleration zero? **3.** The position of a particular particle as a function of time is given by: \[ \mathbf{r} = (9.60 t \, \mathbf{i} + 8.58 \, \mathbf{j} - 1.00 t^2 \, \mathbf{k}) \text{ meters} \] Determine the particle’s velocity and acceleration as a function of time. --- ### Detailed Explanation: **2.** **(a)** The given function describes the displacement \(\mathbf{r}(t)\) of a particle in uniform rectilinear motion. The displacement is represented by a polynomial equation in terms of time \(t\). **(b)** Uniform rectilinear motion refers to motion in a straight line with uniform (constant) velocity, meaning that both the direction and speed of the motion remain consistent over time. **(c)** To find the average acceleration, you need to calculate the change in velocity over the change in time. The first step is to differentiate the displacement function \(\mathbf{r}(t)\) to find the velocity function \( \mathbf{v}(t) \): \[ \mathbf{v}(t) = \frac{d}{dt}[6t^4 - 2t^3 - 12t^2 + 3t + 3] \] Then, differentiate the velocity function to find the acceleration function \( \mathbf{a}(t) \): \[ \mathbf{a}(t) = \frac{d}{dt} \mathbf{v}(t) \] Evaluate \( \mathbf{a}(t) \)
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