2. A vertical force Pat A and another vertical force F at B which act on the bar shown C300 lb-ft produce a resultant force of 150 lb down at D and a counterclockwise couple C = 300 lb-ft. Find the magnitude and direction of forces P R= 150 lb and F. Given: R = 150 lb and C = 300 lb-ft u at D Required: magnitude of force P acting at A and F acting at B. Solution: The direction of forces P and F are assumed. C300 lb-ft D. R=150 lb Assume the direction of forces P and F. +1 R = Ry = Ey- comp -150 = P-F ------ equation (1 +U M = E MB -150 – 300 = P(3) P = -450 lb substitute in equation 1 The negative sign indicate a wrong assumed direction. -150 = -450 F F = -300 lb Therefore: P = 450 lb downward F = 300 lb upward
2. A vertical force Pat A and another vertical force F at B which act on the bar shown C300 lb-ft produce a resultant force of 150 lb down at D and a counterclockwise couple C = 300 lb-ft. Find the magnitude and direction of forces P R= 150 lb and F. Given: R = 150 lb and C = 300 lb-ft u at D Required: magnitude of force P acting at A and F acting at B. Solution: The direction of forces P and F are assumed. C300 lb-ft D. R=150 lb Assume the direction of forces P and F. +1 R = Ry = Ey- comp -150 = P-F ------ equation (1 +U M = E MB -150 – 300 = P(3) P = -450 lb substitute in equation 1 The negative sign indicate a wrong assumed direction. -150 = -450 F F = -300 lb Therefore: P = 450 lb downward F = 300 lb upward
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Please explain this further for me. Thank you
Transcribed Image Text:2. A vertical force Pat A and another vertical
C%3300 lb-ft
force F at B which act on the bar shown
produce a resultant force of 150 lb down at D
and a counterclockwise couple C = 300 lb-ft.
Find the magnitude and direction of forces P
-4'
%3D
·R 150 lb
and F.
Given: R = 150 lb and C = 300 lb-ft u at D
%3D
Required: magnitude of force P acting at A and F acting at B.
Solution:
The direction of forces P and
F are assumed.
D.
-3'-
R 150 lb
Assume the direction of forces P and F.
+↑ R = Ry = Ey- comp
%3D
%3D
-150 = P -F
%3D
-- equation (1
%3D
-150-300 =
=
P(3)
P = -450 lb ------
---substitute in equation (1
The negative sign indicate a
-150 = -450 F
wrong assumed direction.
F = -300 lb
Therefore:
P = 450 lb downward
F. = 300 lb upward
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