2. A trench mortar fires a shell at angle of 30° with the horizontal with an initial velocity of 500 m/s. (See the diagram.) Find a) its range, R; b) the highest point reached, and c) time before it returns to the same level. Solution: Given: Vo = Vo sin 20 2sin 2( a) R= 9.8 m/s2 R = )2sin2L 2(9.8) Vo sin20 b) H = 2g %3D c) te 2Vo sin 0 20 ) sin( R. %3D 9.8 m/s2

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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H =
2V sin B
total time of flight
29
te =
R = * sin 20
Range, maximum horizontal distance
- time to return to the same level
2) Activity 3: Skill-building Activities
Directions: Solve the following problems. Use the steps as guide.
1. A boy on a 20-m high platform throws a ball at a distance of 5 m. At what speed is the
ball thrown? (See the diagram)
5 т;
20 m ; vertical distance
horizontal distance
Solution: Given : d =
dy =
Find : Vox (Vox = )
20 m
2dy
%3D
Since dy = 5 m, then we need to find the time t, yet from d, =gt2, or t =
2 (20)
sec.
9.8
5 m
5 m
dx
Hence, Vox =
_m/s
%3D
2. A trench mortar fires a shell at angle of 30° with the horizontal with an initial velocity of 500 m/s. (See the
diagram.) Find a) its range, R; b) the highest point reached, and c) time before it returns to the same level.
Solution: Given:
Vo =
Vo sin 20
)2 sin 20
a) R =
9.8 m/s2
R =
Vosin20
)?sin2(
b) H =
2(9.8)
2g
H =
10
2Vo sin e
20
)sin(
R.
c) t =
9.8 m/s2
t =
14.0
Transcribed Image Text:H = 2V sin B total time of flight 29 te = R = * sin 20 Range, maximum horizontal distance - time to return to the same level 2) Activity 3: Skill-building Activities Directions: Solve the following problems. Use the steps as guide. 1. A boy on a 20-m high platform throws a ball at a distance of 5 m. At what speed is the ball thrown? (See the diagram) 5 т; 20 m ; vertical distance horizontal distance Solution: Given : d = dy = Find : Vox (Vox = ) 20 m 2dy %3D Since dy = 5 m, then we need to find the time t, yet from d, =gt2, or t = 2 (20) sec. 9.8 5 m 5 m dx Hence, Vox = _m/s %3D 2. A trench mortar fires a shell at angle of 30° with the horizontal with an initial velocity of 500 m/s. (See the diagram.) Find a) its range, R; b) the highest point reached, and c) time before it returns to the same level. Solution: Given: Vo = Vo sin 20 )2 sin 20 a) R = 9.8 m/s2 R = Vosin20 )?sin2( b) H = 2(9.8) 2g H = 10 2Vo sin e 20 )sin( R. c) t = 9.8 m/s2 t = 14.0
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