2. A tank is initially filled with 100 L of salt solution with a concentration of 0.12 kg/L. At time t = 0, a solution containing 0.2 kg/L of salt is poured into the tank at a rate of 3 L/min. Simultaneously, a drain is opened in the bottom of the tank allowing the solution to leave the tank at a rate of 4 L/min. The tank is well-stirred. Let x(t) represent the amount of salt (in kg) in the tank after t minutes. Find the differential equation and initial condition for which r(t) is a solution. DO NOT SOLVE THE DIFFERENTIAL EQUATION. t)= x' (t) = , x(0) =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**Problem 2: Differential Equation Formulation**

A tank is initially filled with 100 L of salt solution with a concentration of 0.12 kg/L. At time \( t = 0 \), a solution containing 0.2 kg/L of salt is poured into the tank at a rate of 3 L/min. Simultaneously, a drain is opened at the bottom of the tank allowing the solution to leave at a rate of 4 L/min. The tank is well-stirred.

Let \( x(t) \) represent the amount of salt (in kg) in the tank after \( t \) minutes. Determine the differential equation and initial condition for which \( x(t) \) is a solution. **Do not solve the differential equation.**

**Differential Equation Formulation**

\[ x'(t) = \]

**Initial Condition**

\[ x(0) = \]

(Note: The problem provides space for these equations to be filled in but does not solve them.)
Transcribed Image Text:**Problem 2: Differential Equation Formulation** A tank is initially filled with 100 L of salt solution with a concentration of 0.12 kg/L. At time \( t = 0 \), a solution containing 0.2 kg/L of salt is poured into the tank at a rate of 3 L/min. Simultaneously, a drain is opened at the bottom of the tank allowing the solution to leave at a rate of 4 L/min. The tank is well-stirred. Let \( x(t) \) represent the amount of salt (in kg) in the tank after \( t \) minutes. Determine the differential equation and initial condition for which \( x(t) \) is a solution. **Do not solve the differential equation.** **Differential Equation Formulation** \[ x'(t) = \] **Initial Condition** \[ x(0) = \] (Note: The problem provides space for these equations to be filled in but does not solve them.)
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