2. A store has requested a manufacturer to produce pants and sports jackets. For materials, the manufacturer has 660 m2 of cotton textile and 1026 m? of polyester. Every pair of pants (1 unit) needs 1 m? of cotton and 2 m? of polyester. Every jacket needs 1.2 m? of cotton and 1 m? of polyester. Letting x and y represent the number of pants and jackets produced respectively, the problem can be expressed as: x + 1.2y s 660 (cotton) 2x + ys 1026 (polyester) x 2 0,y 20
2. A store has requested a manufacturer to produce pants and sports jackets. For materials, the manufacturer has 660 m2 of cotton textile and 1026 m? of polyester. Every pair of pants (1 unit) needs 1 m? of cotton and 2 m? of polyester. Every jacket needs 1.2 m? of cotton and 1 m? of polyester. Letting x and y represent the number of pants and jackets produced respectively, the problem can be expressed as: x + 1.2y s 660 (cotton) 2x + ys 1026 (polyester) x 2 0,y 20
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![2. A store has requested a manufacturer to produce pants and sports jackets.
For materials, the manufacturer has 660 m2 of cotton textile and 1026 m? of
polyester. Every pair of pants (1 unit) needs 1 m? of cotton and 2 m? of polyester.
Every jacket needs 1.2 m? of cotton and 1 m? of polyester.
Letting x and y represent the number of pants and jackets produced respectively, the
problem can be expressed as:
x+ 1.2y < 660 (cotton)
2x + y s 1026 (polyester)
x2 0, y 20
04:11
a) Graph the inequations above and shade out the feasible region.
1000
-500
500
1000 X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fafd6264f-6389-4d30-9b35-9c0c3c7ad9d8%2F8f3ae8ed-78a1-4b76-84bd-79d00f69fd6b%2Fk7rez0m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. A store has requested a manufacturer to produce pants and sports jackets.
For materials, the manufacturer has 660 m2 of cotton textile and 1026 m? of
polyester. Every pair of pants (1 unit) needs 1 m? of cotton and 2 m? of polyester.
Every jacket needs 1.2 m? of cotton and 1 m? of polyester.
Letting x and y represent the number of pants and jackets produced respectively, the
problem can be expressed as:
x+ 1.2y < 660 (cotton)
2x + y s 1026 (polyester)
x2 0, y 20
04:11
a) Graph the inequations above and shade out the feasible region.
1000
-500
500
1000 X
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